Answer :
(a). The speed of the block is 0.395 m/s.
(b). No
Explanation :
Given that,
Diameter = 20.0 cm
Power = 26.0 MW
Mass = 110 kg
diameter = 20.0 cm
Distance = 100 m
We need to calculate the pressure due to laser
Using formula of pressure

![P_{r}=\dfrac{P}{Ac}Put the value into the formula[tex]P_{r}=\dfrac{26.0\times10^{6}}{\pi\times(10\times10^{-2})^2\times3\times10^{8}}](https://tex.z-dn.net/?f=P_%7Br%7D%3D%5Cdfrac%7BP%7D%7BAc%7D%3C%2Fp%3E%3Cp%3EPut%20the%20value%20into%20the%20formula%3C%2Fp%3E%3Cp%3E%5Btex%5DP_%7Br%7D%3D%5Cdfrac%7B26.0%5Ctimes10%5E%7B6%7D%7D%7B%5Cpi%5Ctimes%2810%5Ctimes10%5E%7B-2%7D%29%5E2%5Ctimes3%5Ctimes10%5E%7B8%7D%7D)

We need to calculate the force
Using formula of force


Put the value into the formula


We need to calculate the acceleration
Using formula of force

Put the value into the formula




(a). We need to calculate speed of the block
Using equation of motion

Put the value into the formula


(b). No because the velocity is very less.
Hence, (a). The speed of the block is 0.395 m/s.
(b). No
Answer:
-2.5m/s²
Explanation:
The acceleration of a body is giving by the rate of change of the body's velocity. It is given by
a = Δv / t ----------------(i)
Where;
a = acceleration (measured in m/s²)
Δv = change in velocity = final velocity - initial velocity (measure in m/s)
t = time taken for the change (measured in seconds(s))
From the question;
i. initial velocity = 5m/s
final velocity = 0 [since the body (ball) comes to rest]
Δv = 0 - 5 = -5m/s
ii. time taken = t = 2s
<em>Substitute these values into equation (i) as follows;</em>
a = (-5m/s) / (2s)
a = -2.5m/s²
Therefore, the acceleration of the ball is -2.5m/s²
NB: The negative sign shows that the ball was actually decelerating.
To solve this exercise it is necessary to use the concepts related to Difference in Phase.
The Difference in phase is given by

Where
Horizontal distance between two points
Wavelength
From our values we have,


The horizontal distance between this two points would be given for

Therefore using the equation we have




Therefore the correct answer is C.
C. The range of a projectile increases with an increase in the angle of launch.