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valentina_108 [34]
3 years ago
7

2. Which of the following accurately describes the effects of temperature changes on solids? A. If the temperature of a solid is

increased, the solid contracts and its volume increases. B. If the temperature of a solid is increased, the solid expands and its volume increases. C. If the temperature of a solid is decreased, the solid contracts and its volume increases. D. If the temperature of a solid is decreased, the solid expands and its volume decreases.
Physics
2 answers:
MaRussiya [10]3 years ago
6 0
<h3><u>Answer;</u></h3>

B. If the temperature of a solid is increased, the solid expands and its volume increases.

<h3><u>Explanation;</u></h3>
  • <u>As temperature increases heat energy is applied to the parts of the solid, thus causing a higher vibration and movement of molecules.</u>
  • <em><u>This causes the molecules to push against one another and thus the overall volume of the solid increases.  The solid may then change state to a liquid state.</u></em>
  • Thus, an increase in temperature, causes the solid to expand and thus an increase in volume.
balandron [24]3 years ago
3 0
<span>B. If the temperature of a solid is increased, the solid expands and its volume increases.</span>
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An ideal refrigerator does 130. 0 j of work to remove 780. 0 j of heat from its cold compartment during each cycle. what is the
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The refrigerator's coefficient of performance is 6.

The heat extracted from the cold reservoir Q cold (i.e., inside a refrigerator) divided by the work W required to remove the heat is known as the coefficient of performance, or COP, of a refrigerator (i.e., the work done by the compressor). The required inside temperature and the outside temperature have a significant impact on the COP.

As the inside temperature of the refrigerator decreases, its coefficient of performance decreases. The coefficient of performance (COP) of refrigeration is always more than 1.

The heat produced in the cold compartment, H = 780.0 J

Work done in ideal refrigerator, W = 130.0 J

Refrigerator's coefficient of performance = H/W

                                                                     = 780/130

                                                                     = 6

Therefore, the refrigerator's coefficient of performance is 6.

Energy conservation requires the exhaust heat to be = 780 + 130

                                                                                          = 910 J

Learn more about  coefficient here:

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2 years ago
The valve in the exit pipe is closed . The density of water is 1000kg / m and the gravitational force on free fall of water is 1
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Answer:

300000

Explanation:

p=30x10x1000=30000pascal

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2 years ago
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One major difference between plant and animal cells is that plant cells are the only ones with A) cellulose. B) lysosomes. C) nu
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The correct answer is A .
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According to the Heisenberg uncertainty principle, if the uncertainty in the speed of an electron is 3.5 × 103 m/s, the uncertai
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Explanation:

It is given that,

Uncertainty in the speed of an electron, \Delta v=3.5\times 10^3\ m/s

According to Heisenberg uncertainty principle,

\Delta x.\Delta p=\dfrac{h}{4\pi}

\Delta x is the uncertainty in the position of an electron

Since, \Delta p=m\Delta v

\Delta x=\dfrac{h}{4\pi.m \Delta v}

\Delta x=\dfrac{6.6\times 10^{-34}}{4\pi\times 9.1\times 10^{-31}\times 3.5\times 10^3}

\Delta x=1.64\times 10^{-8}\ m

So, the uncertainty in its position is 1.64\times 10^{-8}\ m. Hence, this is the required solution.

6 0
3 years ago
10.
myrzilka [38]

Answer:

<em>The new period of oscillation is D) 3.0 T</em>

Explanation:

<u>Simple Pendulum</u>

A simple pendulum is a mechanical arrangement that describes periodic motion. The simple pendulum is made of a small bob of mass 'm' suspended by a thin inextensible string.

The period of a simple pendulum is given by

T=2\pi \sqrt{\frac{L}{g}}

Where L is its length and g is the local acceleration of gravity.

If the length of the pendulum was increased to 9 times (L'=9L), the new period of oscillation will be:

T'=2\pi \sqrt{\frac{L'}{g}}

T'=2\pi \sqrt{\frac{9L}{g}}

Taking out the square root of 9 (3):

T'=3*2\pi \sqrt{\frac{L}{g}}

Substituting the original T:

T'=3*T

The new period of oscillation is D) 3.0 T

4 0
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