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valentina_108 [34]

3 years ago

7

2. Which of the following accurately describes the effects of temperature changes on solids? A. If the temperature of a solid is

increased, the solid contracts and its volume increases. B. If the temperature of a solid is increased, the solid expands and its volume increases. C. If the temperature of a solid is decreased, the solid contracts and its volume increases. D. If the temperature of a solid is decreased, the solid expands and its volume decreases.

2 answers:

MaRussiya [10]3 years ago

6 0

<h3><u>Answer;</u></h3>

B. If the temperature of a solid is increased, the solid expands and its volume increases.

<h3><u>Explanation;</u></h3>

<u>As temperature increases heat energy is applied to the parts of the solid, thus causing a higher vibration and movement of molecules.</u>
<em><u>This causes the molecules to push against one another and thus the overall volume of the solid increases. The solid may then change state to a liquid state.</u></em>
Thus, an increase in temperature, causes the solid to expand and thus an increase in volume.

balandron [24]3 years ago

3 0

<span>B. If the temperature of a solid is increased, the solid expands and its volume increases.</span>

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sergiy2304 [10]

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2 years ago

A particle, whose acceleration is constant, is moving in the negative x direction at a speed of 4.91 m/s, and 12.9 s later the p

Zinaida [17]

Answer:

The particle’s velocity is -16.9 m/s.

Explanation:

Given that,

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Time = 12.9 s

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Before 12.4 sec,

Velocity of particle in negative x direction= 5.32 m/s

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t = time

Put the value into the equation

$a=\dfrac{7.12-(-4.91)}{12.9}$

$a=0.933\ m/s^2$

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Using equation of motion again

$v=u+at$

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$u=-5.321-0.933\times12.4$

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3 years ago

What are the three ways that a person can manipulate light?

BARSIC [14]

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3 years ago

For a damped simple harmonic oscillator, the block has a mass of 1.2 kg and the spring constant is 9.8 N/m. The damping force is

ArbitrLikvidat [17]

Answer:

a) t=24s

b) number of oscillations= 11

Explanation:

In case of a damped simple harmonic oscillator the equation of motion is

m(d²x/dt²)+b(dx/dt)+kx=0

Therefore on solving the above differential equation we get,

x(t)=A₀ $e^{\frac{-bt}{2m}}cos(w't+\phi)=A(t)cos(w't+\phi)$

where A(t)=A₀ $e^{\frac{-bt}{2m}}$

A₀ is the amplitude at t=0 and

$w'$ is the angular frequency of damped SHM, which is given by,

$w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }$

Now coming to the problem,

Given: m=1.2 kg

k=9.8 N/m

b=210 g/s= 0.21 kg/s

A₀=13 cm

a) A(t)=A₀/8

⇒A₀ $e^{\frac{-bt}{2m}}$ =A₀/8

⇒ $e^{\frac{bt}{2m}}=8$

applying logarithm on both sides

⇒ $\frac{bt}{2m}=ln(8)$

⇒ $t=\frac{2m*ln(8)}{b}$

substituting the values

$t=\frac{2*1.2*ln(8)}{0.21}=24s(approx)$

b) $w'=\sqrt{\frac{k}{m}-\frac{b^{2}}{4m^{2}} }$

$w'=\sqrt{\frac{9.8}{1.2}-\frac{0.21^{2}}{4*1.2^{2}}}=2.86s^{-1}$

$T'=\frac{2\pi}{w'}$ , where $T'$ is time period of damped SHM

⇒ $T'=\frac{2\pi}{2.86}=2.2s$

let $n$ be number of oscillations made

then, $nT'=t$

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3 years ago

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Harrizon [31]

Answer:

A.) 42.7 m/s

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A.) If Justin races his Chevy S-10 down highway 37 north for 2,560 meters in 60 seconds, what is his velocity?

Velocity = displacement/time

Velocity = 2560/60

Velocity = 42.67 m/s

B.) The Chevy S-10 started rounding at 10 meters per hour. What is the acceleration at 30 seconds on the highway?

Acceleration = velocity/time

Acceleration = 10/30

Acceleration = 0.33 m/s^2

C.) The S-10 has a force of 30 N. What is the mass of the car?

Force = mass × acceleration

30 = mass × 0.33

Mass = 30/ 0.33

Mass = 90 kg

8 0

2 years ago