Answer:
d = 265 ft
Therefore, an object fall 265 ft in the first ten seconds after being dropped
Explanation:
This scenario can be represented by an arithmetic progression AP.
nth term = a + nd
Where a is the first term given as 2.63 ft.
d is the common difference and is given as 5.3ft.
n is the particular second/time.
To calculate how far the object would fall in the first 10 seconds, we can derive it using the sum of an AP.
d = nth sum = (n/2)(2a+(n-1)d)
Where n = 10 seconds
a = 2.65 ft
d = 5.3 ft
Substituting the values we have;
d = (10/2)(2×2.65 + (10-1)5.3)
d = 265 ft
Therefore, an object fall 265 ft in the first ten seconds after being dropped
Work= Force x Distance
Answer: 7500 Joules
Answer:
The length of time between each transit is the planet's "orbital period", or the length of a year on that particular planet. Not all planets have years as long as a year on the Earth! Some planets discovered by Kepler orbit around their stars so quickly that their years only last about four hours!
I hope it helps.
