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Ksenya-84 [330]
4 years ago
15

An atom with an atomic number of 18 will have how many electrons in its innermost orbit

Chemistry
1 answer:
Paraphin [41]4 years ago
6 0

Answer:

2 electrons

Explanation:

The K shell is the innermost orbit and it contains 2 electrons

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Ca3(PO4)2 + 3 H2SO4 ⟶ 2 H3PO4 + 3 CaSO4
Pachacha [2.7K]

Answer:

The answer to your question is below

Explanation:

Balanced chemical reaction

               Ca₃(PO₄)₂  +  3H₂SO₄   ⇒   2H₃SO₄  +  3CaSO₄

To answer this question just calculate the molar mass of both reactants.

Molar mass of Ca₃(PO₄)₂ = (3 x 40) + (2 x 31) + (8 x 16)

                                         = 120 + 62 + 128

                                         = 310 g

Molar mass of 3H₂SO₄ = 3[(2 x 1) + (1 x 32) + (4 x 16)]

                                      = 3[2 + 32 + 64]

                                      = 3[98]

                                      = 294 g

Conclusion

310 g of Ca₃(PO₄)₂ will react with 294 g of 3H₂SO₄

4 0
3 years ago
Which of the following will sink in a container of mercury with a density of 13.6 g/mL?
Rashid [163]
We are given the density of mercury which is equal to 13.6 g/ml. Substances which sink in this metal should have densities higher than the density of the metal, otherwise they would float. The substance thta would sink in mercury is C. gold
4 0
4 years ago
A type of building that absorbs the energy of seismic waves is a fixed-base building. True or False
dexar [7]
Your answer is <span>False, its base isolated building.</span>
3 0
3 years ago
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How many moles of aluminum are in 4.35 moles of al2si4o10(OH)2
Gnoma [55]

Answer:

8.7 mol Al

Explanation:

You have the compound Al₂Si₄O₁₀(OH)₂.  Within the compound, you have atoms.  You can tell how many atoms there are by looking at the subscript.  You have 2 aluminum atoms, giving you 8.7 moles of aluminum.

4.35 × 2 = 8.7

6 0
4 years ago
In 2 hours a bicyclist traveled 75 kilometers. What was the bicyclist's average speed?
sleet_krkn [62]

Answer:

37.5 miles per hour....

7 0
3 years ago
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