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Nikitich [7]
3 years ago
9

Two charged concentric spherical shells have radii of 11.0 cm and 14.0 cm. The charge on the inner shell is 3.50 ✕ 10−8 C and th

at on the outer shell is 1.60 ✕ 10−8 C. Find the magnitude of the electric field at the following points.
Physics
1 answer:
Sergio039 [100]3 years ago
7 0

Answer:

The magnitude of the electric field are 2.38\times10^{4}\ N/C and 1.09\times10^{4}\ N/C

Explanation:

Given that,

Radius of inner shell = 11.0 cm

Radius of outer shell = 14.0 cm

Charge on inner shell q_{inn}=3.50\times10^{-8}\ C

Charge on outer shell q_{out}=1.60\times10^{-8}\ C

Suppose, at r = 11.5 cm and at r = 20.5 cm

We need to calculate the magnitude of the electric field at r = 11.5 cm

Using formula of electric field

E=\dfrac{kq}{r^2}

Where, q = charge

k = constant

r = distance

Put the value into the formula

E=\dfrac{9\times10^{9}\times3.50\times10^{-8}}{(11.5\times10^{-2})^2}

E=2.38\times10^{4}\ N/C

The total charge enclosed  by a radial distance 20.5 cm

The total charge is

q=q_{inn}+q_{out}

Put the value into the formula

q=3.50\times10^{-8}+1.60\times10^{-8}

q=5.1\times10^{-8}\ C

We need to calculate the magnitude of the electric field at r = 20.5 cm

Using formula of electric field

E=\dfrac{kq}{r^2}

Put the value into the formula

E=\dfrac{9\times10^{9}\times5.1\times10^{-8}}{(20.5\times10^{-2})^2}

E=1.09\times10^{4}\ N/C

Hence, The magnitude of the electric field are 2.38\times10^{4}\ N/C and 1.09\times10^{4}\ N/C

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You can tell a lot about an object that's not moving,
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==> If the box is at rest on the table, then it is not accelerating.

==> Since it is not accelerating, I can say that the forces on it are balanced.

==> That means that the sum of all forces acting on the box is zero,
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==> This in turn means that all of the horizontal forces are balanced,
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Vertical forces:
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What did physicist James Joule's famous paddle wheel experiment demonstrate?
PilotLPTM [1.2K]

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A. that the initial gravitational potential energy of the masses transformed into kinetic energy of the paddles and then to thermal energy in the water


<u>Explanation</u>

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Answer:

The minimum coefficient of friction is 0.22

Explanation:

Suppose If a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve.

We need to calculate the ideal speed to take a 85 m radius curve banked at 15°.

Given that,

Radius = 85 m

Angle = 15°

Speed = 20 km/h

We need to calculate the ideal speed

Using formula of speed

\tan\theta=\dfrac{v^2}{rg}

v=\sqrt{rg\tan\theta}

Put the value into the formula

v=\sqrt{85\times9.8\tan15}

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Using formula for coefficient of friction

v^2=\dfrac{rg(\sin\theta-\mu\cos\theta)}{\mu\sin\theta+\cos\theta}

Put the value into the formula

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A uniform, thin rod of length L and mass M is allowed to pivot about its end. The rotational inertia of a rod about its end is M
weeeeeb [17]

Answer:

g = \frac{V_B^2}{L}  =  \frac{\Delta y}{\Delta x}

Explanation:

Given that :

length of the thin rod = L

mass = m

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The experimental design that the student can use to conduct the experimental value of g can be determined as follow:

Taking the integral value of I

I =\int\limits \  r^2  \, dm

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I =\int\limits^L_0 { \lambda r^2 } \, dr

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L = horizontal axis

V_B^2 = 3gL     ( y = mx)

3g = \frac{V_B^2}{L}

g = \frac{V_B^2}{L}  =  \frac{\Delta y}{\Delta x}

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4 years ago
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