An airplane flies east at a speed of 120 m/s the airplane has a mass of 3200
1 answer:
1) The momentum of the airplane is east
2) The impulse applied to the airplane is 32,000 kg m/s west
Explanation:
1)
The momentum of an object is defined as
where
m is the mass of the object
v is its velocity
The airplane in this problem has
m = 3200 kg is its mass
v = 120 m/s east is its velocity
So, its momentum is
And since momentum is a vector, it also has a direction, which is the same as the velocity (east).
2)
The impulse applied to an object is equal to the change in momentum of the object:
where
m is the mass
v is the final velocity
u is the initial velocity
For the airplane in this problem,
m = 3200 kg
u = 120 m/s
v = 110 m/s
So, the impulse is
And the negative sign means the direction of the impulse is opposite to the airplane motion, so west.
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Answer:
Positive z direction.
Explanation:
The magnetic force acting on the electron is given by the formula as :
q is the charge on proton
v is the speed of proton
B is the magnetic field
It is mentioned that the proton is moving with a velocity in the positive x-direction. The uniform magnetic field B in the positive y-direction such taht,
q = +e
v = vi
B = Bj
Since,
So, the magnetic force acting on the proton in positive z axis. Hence, the correct option is (d) "positive z direction".
The given question is incomplete. The complete question is as follows.
Measurements show that the enthalpy of a mixture of gaseous reactants decreases by 338 kJ during a certain chemical reaction, which is carried out at a constant pressure. Furthermore, by carefully monitoring the volume change it is determined that 187 kJ of work is done on the mixture during the reaction. Calculate the change in energy of the gas mixture during the reaction. Be sure your answer has the correct number of significant digits. Is the reaction exothermic or endothermic ?
Explanation:
The given data is as follows.
Change in enthalpy () = -338 kJ (as it is a decrease)
Work done = 187 kJ,
Change in energy () = ?
Now, according to the first law of thermodynamics the formula is as follows.
Hence, putting the given values into the above formula as follows.
Also, we know that W =
so,
= -151 kJ
Thus, we can conclude that the change in energy of the gas mixture during the reaction is -151 kJ.