An airplane flies east at a speed of 120 m/s the airplane has a mass of 3200
1 answer:
1) The momentum of the airplane is east
2) The impulse applied to the airplane is 32,000 kg m/s west
Explanation:
1)
The momentum of an object is defined as
where
m is the mass of the object
v is its velocity
The airplane in this problem has
m = 3200 kg is its mass
v = 120 m/s east is its velocity
So, its momentum is
And since momentum is a vector, it also has a direction, which is the same as the velocity (east).
2)
The impulse applied to an object is equal to the change in momentum of the object:
where
m is the mass
v is the final velocity
u is the initial velocity
For the airplane in this problem,
m = 3200 kg
u = 120 m/s
v = 110 m/s
So, the impulse is
And the negative sign means the direction of the impulse is opposite to the airplane motion, so west.
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Answer:
a) 2.41 km
b) 38.8°
Questions c and d are illegible.
Explanation:
We can express the displacements as vectors with origin on the point he started (0, 0).
When he traveled south he moved to (-3, 0).
When he moved east he moved to (-3, x)
The magnitude of the total displacement is found with Pythagoras theorem:
d^2 = dx^2 + dy^2
Rearranging:
dy^2 = d^2 - dx^2
The angle of the displacement vector is:
cos(a) = dx/d
a = arccos(dx/d)
a = arccos(3/3.85) = 38.8°
Answer:
The work done on the box is 80 J.
Explanation:
Given that,
Weight of box = 40 N
Distance = 2 meter
We need to calculate the work done
Using formula of work done
Where, x = distance
mg = weight
Put the value into the formula
Hence, The work done on the box is 80 J.