Ask question

Ask question

All categories

3 years ago

11

A proton travels with a speed of 5.05 ✕ 106 m/s at an angle of 64° with the direction of a magnetic field of magnitude 0.160 T i

n the positive x-direction.(a) What is the magnitude of the magnetic force on the proton? N
(b) What is the proton's acceleration? m/s2

2 answers:

Natali [406]3 years ago

7 0

Answer:

(a) the magnitude of the magnetic force on the proton is 1.16 x 10⁻¹³ N

(b) the proton's acceleration is 6.97 x 10¹³ m/s²

Explanation:

given information:

proton's speed, v = 5.05 ✕ 10⁶ m/s

angle, θ = 64°

magnetic field, B = 0.160 T ( +x direction)

(a) the magnitude of the magnetic force on the proton

F = q v B sin θ

where

F = magnetic force (N)

q = charge (C)

v = speed (m/s)

B = magnetic field (T)

θ = angle

F = q v B sin θ

proton charge, q = 1.602 x 10⁻¹⁹ C

thus,

F = (1.602 x 10⁻¹⁹) (5.05 ✕ 10⁶) (0.160) sin 64°

= 1.16 x 10⁻¹³ N

the proton's acceleration

F = m a

where

m = mass (kg)

a = acceleration (m/s²)

the mass of proton, m = 1.67 x 10⁻²⁷ kg

so,

F = m a

a = F/m

= (1.16 x 10⁻¹³)/(1.67 x 10⁻²⁷)

= 6.97 x 10¹³ m/s²

Setler [38]3 years ago

4 0

Answer:

A. 1.19 * 10^(-13) N

B. 7.12 * 10^(15) m/s²

Explanation:

Parameters given:

Speed, v = 5.05 * 10^6 m/s

Angle, A = 64°

Magnetic field strength, B = 0.160T

Mass of proton, m = 1.673 * 10^(-27) kg

Charge of proton, q = 1.6023 * 10^(-19) C

A. Magnetic force is given as:

F = q*v*B*sinA

F = 1.6023 * 10^(-19) * 5.05 * 10^6 * 0.160 * sin64

F = 1.19 * 10^(-13) N

B. Force is generally given as:

F = m*a

Hence, we can find acceleration, a, by making it the subject of formula:

a = F/m

a = (1.19 * 10^(-13))/(1.673 * 10^-27)

a = 7.12 * 10^15 m/s²

You might be interested in

Why cant people with aids foght out the infection?

sveta [45]

They can fight the infection but not the disease

3 0

3 years ago

Read 2 more answers

A mass weighing 24 pounds, attached to the end of a spring, stretches it 4 inches. Initially, the mass is released from rest fro

svetoff [14.1K]

Answer:

The equation of motion is $x(t)=-$ $\frac{1}{3} cos4\sqrt{6t}$

Explanation:

Lets calculate

The weight attached to the spring is 24 pounds

Acceleration due to gravity is $32ft/s^2$

Assume x , is spring stretched length is ,4 inches

Converting the length inches into feet $x=\frac{4}{12} =\frac{1}{3}feet$

The weight (W=mg) is balanced by restoring force ks at equilibrium position

mg=kx

$W=kx$ ⇒ $k=\frac{W}{x}$

The spring constant , $k=\frac{24}{1/3}$

= 72

If the mass is displaced from its equilibrium position by an amount x, then the differential equation is

$m\frac{d^2x}{dt} +kx=0$

$\frac{3}{4} \frac{d^2x}{dt} +72x=0$

$\frac{d^2x}{dt} +96x=0$

Auxiliary equation is, $m^2+96=0$

$m=\sqrt{-96}$

= $\frac{+}{} i4\sqrt{6}$

Thus , the solution is $x(t)=c_1cos4\sqrt{6t}+c_2sin4\sqrt{6t}$

$x'(t)=-4\sqrt{6c_1} sin4\sqrt{6t}+c_2$ $4\sqrt{6}$ $cos4\sqrt{6t}$

The mass is released from the rest x'(0) = 0

$=-4\sqrt{6c_1} sin4\sqrt{6(0)}+c_2$ $4\sqrt{6}$ $cos4\sqrt{6(0)}$ =0

$c_2$ $4\sqrt{6} =0$

$c_2=0$

Therefore , $x(t)=c_1$ $cos 4\sqrt{6t}$

Since , the mass is released from the rest from 4 inches

$x(0)= -4$ inches

$c_1 cos 4\sqrt{6(0)} =-\frac{4}{12}$ feet

$c_1=-\frac{1}{3}$ feet

Therefore , the equation of motion is $-\frac{1}{3} cos4\sqrt{6t}$

7 0

2 years ago

4. Why do you think people in south Louisiana specialize in seafood?

lbvjy [14]

Answer:

gang

Explanation:

yupppp

7 0

3 years ago

which of the following locations has the largest electric field? A)0.4 cm from a +3.0 uC point charge B)0.2 cm frm a +1.5 uC poi

JulsSmile [24]

<span>Electric field is proportional to q/d^2, where q is the magnitude of the charge and d is the distance. Since all the given units are identical, we can just compare their relative magnitudes without calculating for the exact values.
A) 3/(0.4)^2 = 18.75
B) 1.5/(0.2)^2 = 37.5
C) 6/(0.4)^2 = 37.5
D) 3/(0.2)^2 = 75
Therefore, choice D has the largest electric field of all.
</span>

7 0

3 years ago

Two point sources, vibrating in phase, produce an interferencepattern in a ripple tank. If the frequency is increased by 20%, th

Vera_Pavlovna [14]

Answer:

option A

Explanation:

given,

frequency is increased by 20%

we know,

$\dfrac{x_n}{L}d = (n-\dfrac{1}{2})\times \lambda$ ...........(1)

where

x_n is the perpendicular distance between the point the interference pattern is obtained,

L is the distance between the center of the two point sources

and λ is the wavelength of light.

If the frequency is increased by 20%, then the number of nodal lines is increased by 20%.

From equation (1),we observe that the frequency is directly proportional to the number of nodal lines.

Hence, the correct answer is option A

8 0

3 years ago