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Nimfa-mama [501]
3 years ago
11

How should the table be changed to correctly distinguish between mechanical and electromagnetic waves? Earthquake waves and radi

ation waves need to change places. Light waves and X-ray waves need to change places. Ocean waves and X-ray waves need to change places. Sound waves and light waves need to change places. ...the answer is D
Physics
2 answers:
Agata [3.3K]3 years ago
6 0

Answer:

Electromagnetic waves are visible; mechanical waves are invisible. Electromagnetic waves always reflect; mechanical waves always refract.

Explanation:

erma4kov [3.2K]3 years ago
5 0

Answer:

well you already answered yourself i don't see why you would waist points to do that but yes you are correct .

Explanation:

stay safe and where a mask 2021

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Can someone complete this assignment will give brainliest!<br> The assignment is attached
Musya8 [376]
... I can’t see the attached assignment that you put on here.
3 0
3 years ago
What is 6.39 times 10 to the 23rd power
Sveta_85 [38]

Answer:

6.39*(10 to the 23rd)=

6.39*10²³

6 0
3 years ago
What is the resultant of a pair of one pound forces at right angles to each other?
OleMash [197]

Answer:

F_R=\sqrt{2} \ pound.force

Explanation:

Given that there are two force of 1 pound each at right angles to each other.

The from the vector law of addition:

F_R=\sqrt{F_1^2+F_2^2}

where:

F_R= resultant force

F_1\ \&\ F_2 be the two of the forces to be added.

F_R=\sqrt{1^2+1^2}

F_R=\sqrt{2} \ pound.force

8 0
4 years ago
Why are some forces considered to be noncontact forces? A. Objects must be far apart in order to exert a force. B. Objects do no
kompoz [17]

Answer:

B. Objects do not have to touch each other to experience a force.

Explanation:

For example ..One of the noncontact forces is magnetic force whereby a magnetic object will be attracted to another magnetic object of oppsite charged particles, through waves called electromagnetic waves. On the other hand, the two magnetic objects of similar charged particles can repel through electromagnetic waves..

8 0
3 years ago
mass of the planet is 12 times that of earth and its radius is thrice that of earth , then find the escape velocity on that plan
Over [174]

Answer:

The escape velocity on the planet is approximately 178.976 km/s

Explanation:

The escape velocity for Earth is therefore given as follows

The formula for escape velocity, v_e, for the planet is v_e = \sqrt{\dfrac{2 \cdot G \cdot m}{r} }

Where;

v_e = The escape velocity on the planet

G = The universal gravitational constant = 6.67430 × 10⁻¹¹ N·m²/kg²

m = The mass of the planet = 12 × The mass of Earth, M_E

r = The radius of the planet = 3 × The radius of Earth, R_E

The escape velocity for Earth, v_e_E, is therefore given as follows;

v_e_E = \sqrt{\dfrac{2 \cdot G \cdot M_E}{R_E} }

\therefore v_e = \sqrt{\dfrac{2 \times G \times 12 \times M}{3 \times R} } =  \sqrt{\dfrac{2 \times G \times 4 \times M}{R} } = 16 \times \sqrt{\dfrac{2 \times G \times M}{R} } = 16 \times v_e_E

v_e = 16 × v_e_E

Given that the escape velocity for Earth, v_e_E ≈ 11,186 m/s, we have;

The escape velocity on the planet = v_e ≈ 16 × 11,186 ≈ 178976 m/s ≈ 178.976 km/s.

3 0
3 years ago
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