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3 years ago

Which of these describes an endothermic process?

Chemistry

2 answers:

vfiekz [6]3 years ago

4 0

Answer:

3rd one

Explanation:

"when barium hydroxide is mixed with ammonium chloride, ice crystals form on the outside of the container" is the correct answer to describe the endothermic process.

Phoenix [80]3 years ago

3 0

The third one down: "When barium hydroxide is mixed with ammonium chloride, ice crystals form on the outside of the container."

This is because an endothermic reaction [process] takes in more energy than it releases. Therefore because a decrease in energy leads to a decrease in temperature, the ice crystals forming show that it must be a endothermic reaction [process].

Hope this helps! :)
AJ

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Bond [772]

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3 years ago

Help I Will Mark Brainlist !! (ATTACHED IMAGE BELOW) Which of the diagrams below would be the FASTEST? _____ Why? Which of the d

VLD [36.1K]

Answer:

Fastest C. Reaction time is faster

Slowest A. Reaction time is slower and it takes longer to finish

Explanation:

4 0

2 years ago

NH4NO3 + Na3PO4 → (NH4)3PO4 + NaNO3

Papessa [141]

Based on the equation of the reaction and the data provided,

NH4NO3 is the limiting reactant
mass of Na3PO4 left is 29.375 g
18.75 g of (NH4)3PO4 is produced
31.875 g of NaNO3 is produced

<h3>What are limiting reactants?</h3>

A limiting reactant is a reactant which is used up in a reaction after which the reaction stops.

In the given reaction:

3 NH4NO3 + Na3PO4 → (NH4)3PO4 + 3 NaNO3

The limiting reactant is determined from the stoichiometry of the eqaution.

Moles of reactant = mass/molar mass

Molar mass of NH4NO3 = 80 g/mol

Molar mass of Na3PO4 = 165 g/mol

Molar mass of (NH4)3PO4 = 150 g/mol

Molar mass of NaNO3 = 85 g/mol

From the equation of the reaction, 240 g (3 × 80) of NH4NO3 is required to react with 165 g of Na3PO4

There are only 30.0 g of NH4NO3 reacting with 50.0 g of Na3PO4

30 g of Na3PO4 will react with 30 × 165/240 = 20.625 g of Na3PO4

Therefore, NH4NO3 is the limiting reactant

Na3PO4 is the excess reactant

mass of Na3PO4 left = 50 - 20.625

mass of excess reactant left = 29.375 g

moles of NH4NO3 in 30 g = 30/80 = 0.375 moles

3 moles of NH4NO3 produces 1 mole of (NH4)3PO4

0.375 moles of NH4NO3 will produce 0.375 × 1/3 = 0.125 moles of (NH4)3PO4

mass of 0.125 moles of (NH4)3PO4 = 0.125 × 150

mass of (NH4)3PO4 produced = 18.75 g of (NH4)3PO4

3 moles of NH4NO3 produces 3 moles of NaNO3

0.375 moles of NH4NO3 will produce 0.375 moles of NaNO3

mass of 0.375 moles of NaNO3 = 0.375 × 85

mass of NaNO3 produced = 31.875 g of NaNO3

Learn more about limiting reactant at: brainly.com/question/24945784

4 0

2 years ago

In the reaction Mg (s) + 2HCl (aq) H2 (g) + MgCl2 (aq), how many grams of hydrogen gas will be produced from 125.0 milliliters o

Murrr4er [49]

Since the Mg is in excess, therefore HCl will be fully consumed in the reaction.

The first step is to find the amount of HCl in mol

Let N (HCl) = amount of HCl in mol

N (HCl) = (6 mol HCL/L solution) *( 125 mL ) * (1 L/1000 mL) = 0.75 mol of HCl

Through stoichiometry

N (H2) = 0.75 mol HCl * (1 mol H2/ 2 mol of HCl)

N(H2) = 0.375 mol H2

Since we are asked for the number of grams of H2 (mass), we multiply this with the molar mass of hydrogen

M (H2) = 0.375 mol H2 ( 2 g H2 / 1 mol H2)

M (H2) = 0.75 g H2

6 0

4 years ago

Rank these elements in order from lowest to highest ionization energies: Cr, K, Ba, F

Aliun [14]

Answer: F, K, Ba, Cr

6 0

4 years ago