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Kay [80]
2 years ago
14

When the resistance of a circuit is doubled, and no other changes occur, what effect does this have on this current in the circu

it?
Physics
1 answer:
liraira [26]2 years ago
3 0

As a result of doubled resistance, current will be halved.

As we know, Ohm's law inversely relates current and resistance to each other. The equation is as follows -

V = I*R, where V is voltage, I is current and R is resistance.

As the question mentions no change in any other parameter, let's assume I₁ and I₂ be initial and final current and R₁ and R₂ initial and final resistance.

So, R₂ will be 2R₁ as it is doubled.

Now, equating the values and finding out the value of final current.

I₁R₁ =  I₂R₂

Keep the value of R₂

I₁R₁ =  I₂2R₁

Cancelling R₁ as it is common on both sides of equation.

So, we get - I₁ =  2I₂

I₂ = I₁/2

Thus, as can be seen above, final current will be half of initial current.

Learn more about Ohm's law and relation between current, voltage and resistance -

brainly.com/question/796939

#SPJ4

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Take a look at a simple reaction like the one below:

In this reaction some reactant A is turned into some product B. The rate of reaction can be represented by a decrease in concentration of A over time or as the increase of B over time. This is written:

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Can you label the parts of the eye?
photoshop1234 [79]

Answer:

  1. Iris
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3 years ago
On a straight, level, two-lane road, two cars moving in opposite directions approach and pass each other. Car A is in the eastbo
ludmilkaskok [199]

Answer:

a) 42 m/s, positive direction (to the east), b) 42 m/s, negative direction (to the west).

Explanation:

a) Let consider that Car A is moving at positive direction. Then, the relative velocity of Car A as seen by the driver of Car B is:

\vec v_{A/B} = \vec v_{A} - \vec v_{B}\\\vec v_{A/B} = 11 \frac{m}{s} \cdot i + 31 \frac{m}{s} \cdot i\\\vec v_{A/B} = 42 \frac{m}{s} \cdot i

42 m/s, positive direction (to the east).

b) The relative velocity of Car B as seen by the drive of Car A is:

\vec v_{B/A} = \vec v_{B} - \vec v_{A}\\\vec v_{B/A} = -31 \frac{m}{s} \cdot i - 11 \frac{m}{s} \cdot i\\\vec v_{B/A} = - 42 \frac{m}{s} \cdot i

42 m/s, negative direction (to the west).

5 0
3 years ago
Train cars are coupled together by being bumped into one another. Suppose two loaded train cars are moving toward one another, t
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Answer:

0.243 m/s

Explanation:

From law of conservation of motion,

mu+m'u' = V(m+m')................. Equation 1

Where m = mass of the first car, m' = mass of the second car, initial velocity of the first car, u' = initial velocity of the second car, V = Final velocity of both cars.

make V the subject of the equation

V = (mu+m'u')/(m+m')................. Equation 2

Given: m = 260000 kg, u = 0.32 m/s, m' = 52500 kg, u' = -0.14 m/s

Substitute into equation 2

V = (260000×0.32+52500×(-0.14))/(260000+52500)

V = (83200-7350)/312500

V = 75850/312500

V = 0.243 m/s

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Degger [83]

Answer:

The Moon revolves or moves around the Earth in a path called its orbit and rotates, or spins, in space.

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