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Kay [80]
1 year ago
14

When the resistance of a circuit is doubled, and no other changes occur, what effect does this have on this current in the circu

it?
Physics
1 answer:
liraira [26]1 year ago
3 0

As a result of doubled resistance, current will be halved.

As we know, Ohm's law inversely relates current and resistance to each other. The equation is as follows -

V = I*R, where V is voltage, I is current and R is resistance.

As the question mentions no change in any other parameter, let's assume I₁ and I₂ be initial and final current and R₁ and R₂ initial and final resistance.

So, R₂ will be 2R₁ as it is doubled.

Now, equating the values and finding out the value of final current.

I₁R₁ =  I₂R₂

Keep the value of R₂

I₁R₁ =  I₂2R₁

Cancelling R₁ as it is common on both sides of equation.

So, we get - I₁ =  2I₂

I₂ = I₁/2

Thus, as can be seen above, final current will be half of initial current.

Learn more about Ohm's law and relation between current, voltage and resistance -

brainly.com/question/796939

#SPJ4

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An airplane traveling at 201 m/s makes a turn. What is the smallest radius of the circular path (in km) that the pilot can make
egoroff_w [7]

Answer:

the smallest radius of the circular path is 8.1 km

Explanation:

The computation of the smallest radius of the circular path is given below:

Given that

V = Velocity = 201 m/s

a_c = acceleration = 5 m/s^2

radius = ?

As we know that

a_c = V^2 ÷ r

5 = 201^2 ÷ r

r = 201^2 ÷ 5

= 8,080.2 g

= 8.1 km

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4 0
2 years ago
A 15 n force directed to the west acts on an object for 3.0 seconds, what is the change in momentum of the object?
pickupchik [31]
By definition we have that
 force=dP/dt,
 where
 p is momentum
 so
 <span>momentum is force*time
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 </span><span>the change in momentum of the object is 45 N.s</span>
7 0
3 years ago
A 5 kg ball of clay is moving with a speed of 25 m/s directly toward a 10 kg ball of clay which is at rest. The two clay balls c
Dafna11 [192]

Answer:

8.3m/s

Explanation:

Given parameters:

mass of clay ball  = 5kg

Speed of clay ball  = 25m/s

mass of clay ball at rest  = 10kg

speed of clay ball at rest  = 0m/s

Unknown:

Velocity after collision  = ?

Solution:

 Since the balls stick together, this is an inelastic collision:

   m1v1 + m2v2  = v(m1 + m2)

  5(25) + 10(0)  =  v (5 + 10)

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7 0
2 years ago
In unit-vector notation, what is the torque about the origin on a particle located at coordinates (0 m, −3.0 m, 2.0 m) due to fo
irinina [24]

Answer:

The torque about the origin is 2.0Nm\hat{i}-8.0Nm\hat{j}-12.0Nm\hat{k}

Explanation:

Torque \overrightarrow{\tau} is the cross  product between force \overrightarrow{F} and vector position \overrightarrow{r} respect a fixed point (in our case the origin):

\overrightarrow{\tau}=\overrightarrow{r}\times\overrightarrow{F}

There are multiple ways to calculate a cross product but we're going to use most common method, finding the determinant of the matrix:

\overrightarrow{r}\times\overrightarrow{F} =-\left[\begin{array}{ccc} \hat{i} & \hat{j} & \hat{k}\\ F1_{x} & F1_{y} & F1_{z}\\ r_{x} & r_{y} & r_{z}\end{array}\right]

\overrightarrow{r}\times\overrightarrow{F} =-((F1_{y}r_{z}-F1_{z}r_{y})\hat{i}-(F1_{x}r_{z}-F1_{z}r_{x})\hat{j}+(F1_{x}r_{y}-F1_{y}r_{x})\hat{k})

\overrightarrow{r}\times\overrightarrow{F} =-((0(2.0m)-0(-3.0m))\hat{i}-((4.0N)(2.0m)-(0)(0))\hat{j}+((4.0N)(-3.0m)-0(0))\hat{k})

\overrightarrow{r}\times\overrightarrow{F}=-2.0Nm\hat{i}+8.0Nm\hat{j}+12.0Nm\hat{k}=\overrightarrow{\tau}

4 0
3 years ago
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