Whenever light goes from transparent to another medium or from rarer to denser medium or vice versa, it's speed changes and hence light bends.
Answer:
The track's angular velocity is W2 = 4.15 in rpm
Explanation:
Momentum angular can be find
I = m*r^2
P = I*W
So to use the conservation
P1 + P2 = 0
I1*W1 + I2*W2 = 0
Solve to w2 to find the angular velocity
0.240kg*0.30m^2*0.79m/s=-1kg*0.30m^2*W2
W2 = 0.435 rad/s
W2 = 4.15 rpm
Answer:
1.718 N , attractive
Explanation:
r = 0.66 m, n = 5.7 x 10^13
q1 = 5.7 x 10^13 x 1.6 x 10^-19 = 9.12 x 10^-6 C
q2 = - 5.7 x 10^13 x 1.6 x 10^-19 = - 9.12 x 10^-6 C
F = K q1 q2 / r^2
F = 9 x 10^9 x 9.12 x 10^-6 x 9.12 x 10^-6 / (0.66)^2
F = 1.718 N
As both the charges are opposite in nature, so the force between them is attractive.
Answer:
Induced EMF,
Explanation:
Given that,
Radius of the circular loop, r = 5 cm = 0.05 m
Time, t = 0.0548 s
Initial magnetic field, 
Final magnetic field, 
The expression for the induced emf is given by :
= magnetic flux
So, the induced emf in the loop is 0.0143 volts. Hence, this is the required solution.
