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vlada-n [284]
3 years ago
13

What do radio waves and gamma rays have in common?

Physics
2 answers:
Irina-Kira [14]3 years ago
5 0

Answer:

A- They are both electromagnetic waves

I took the test and this was the answer

Explanation:

Nastasia [14]3 years ago
4 0

Answer:

A - They are both electromagnetic waves.

Explanation:

Electromagnetic waves are waves consisting of periodic oscillations of electric and magnetic fields, that vibrate in a plane perpendicular to the direction of propagation of the wave (for this reason, they are said to be "transverse waves").

Electromagnetic waves, unlike mechanical waves, can travel through a vacuum, and do not need a medium to propagate. Their speed in a vacuum is a constant and it is called speed of light (c=3.0\cdot 10^8 m/s).

Electromagnetic waves are classified, depending on their wavelength and frequency, into 7 different types - together they form the electromagnetic spectrum. The 7 types, listed from shortest to longest wavelength, are:

gamma rays

X-rays

ultraviolet radiation

visible light

infrared radiation

microwaves

radio waves

All these waves, despite having different properties, are all electromagnetic waves -so we see that both radio waves and gamma rays belong to this type of waves.

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7 0
3 years ago
Is energy transformation from potential to kinetic 100%?
Arada [10]
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Fynjy0 [20]

Answer:

it change speed

Explanation:

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3 0
3 years ago
The earth rotates once per day about an axis passing through the north and south poles, an axis that is perpendicular to the pla
Vladimir [108]

Answer

given,

Radius of sphere = 6.38 × 10⁶ m

time  = 1 day = 86400 s

\omega = \dfrac{2\pi}{T}

\omega = \dfrac{2\pi}{ 86400 }

\omega = 7.272 \times 10^{-5}\ rad/s

a) at equator

v = R_E \omega

v = 6.38 \times 10^6\times 7.272 \times 10^{-5}

v = 464 m/s

acceleration of the person

a = \omega^2R_E

a = (7.272 \times 10^{-5})^2(6.38 \times 10^6)

a = 0.03374 m/s^2

b) at a latitude of 61.0 ° north of the equator.

R = R_E cos \theta

R = 6.38 \times 10^6\times cos 61^0

R = 3.093 \times 10^6 m

v = R \omega

v = 3.093 \times 10^6 \times 7.272 \times 10^{-5}

v = 225 m/s

acceleration of the person

a = \omega^2R_E

a = (7.272 \times 10^{-5})^2(3.093 \times 10^6 )

a = 0.01635 m/s^2

4 0
3 years ago
Convert 200in/10s into m/s (1m = 39.37in)
stiv31 [10]
5.08




hope you got it right !
7 0
4 years ago
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