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2 years ago

What were the key factors that made the wright brothers’ wind tunnel a useful tool for wing design?

Physics

2 answers:

Anna71 [15]2 years ago

7 0

Answer:

Balancing equipment.

Explanation:

The wind tunnel made by Wright's brother was made up of a wooden box with glasses on it to see the inner instruments work.

The key factor that made the Wright's brother wind tunnel a useful tool for wind design is the balancing equipment used in it. It was designed to measure lift and drag. Old hacksaw blades and bicycle spokes were used to make the balances which measure the forces of lift and drag action on a wing.

IrinaK [193]2 years ago

5 0

The Wright brothers built a wind tunnel<span> and developed model-testing </span>techniques<span> including a </span>balance to more accurately determine the lift and drag of their aircraft. I hope my answer has come to your help. God bless and have a nice day ahead!

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A bicycle is a compound machine, true or false

JulsSmile [24]

This is true. The break handles and brakes are levers and the seat adjustment (raise or lower) is a screw.

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3 years ago

Read 2 more answers

A stretched string has a mass per unit length of 5.40 g/cm and a tension of 17.5 N. A sinusoidal wave on this string has an ampl

kondaur [170]

Answer:

Part a)

$y_m = 0.157 mm$

part b)

$k = 101.8 rad/m$

Part c)

$\omega = 579.3 rad/s$

Part d)

here since wave is moving in negative direction so the sign of $\omega$ must be positive

Explanation:

As we know that the speed of wave in string is given by

$v = \sqrt{\frac{T}{m/L}}$

so we have

$T = 17.5 N$

$m/L = 5.4 g/cm = 0.54 kg/m$

now we have

$v = \sqrt{\frac{17.5}{0.54}}$

$v = 5.69 m/s$

now we have

Part a)

$y_m$ = amplitude of wave

$y_m = 0.157 mm$

part b)

$k = \frac{\omega}{v}$

here we know that

$\omega = 2\pi f$

$\omega = 2\pi(92.2) = 579.3 rad/s$

so we have

$k = \frac{579.3}{5.69}$

$k = 101.8 rad/m$

Part c)

$\omega = 579.3 rad/s$

Part d)

here since wave is moving in negative direction so the sign of $\omega$ must be positive

4 0

3 years ago

1. Compare the speed that light waves travel in air to the speed that sound waves travel in the air. How many times faster do li

Vladimir79 [104]

Answer:

895522 times faster.

Explanation:

From the question given above, the following data were obtained:

Speed of sound in air (v) = 335 m/s

Speed of light in air (c) = 3×10⁸ m/s

How many times faster =.?

To obtain how many times faster light travels in air than sound, do the following

c : v => 3×10⁸ : 335

c/v = 3×10⁸ / 335

c/v = 895522

Cross multiply

c = 895522 × v

From the illustrations made above, we can see that the speed of the light in air (c) is 895522 times the speed of sound in air.

Thus, light travels 895522 times faster than sound in air.

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2 years ago

) Water flows through a horizontal coil heated from the outside by high-temperature flue gases. As it passes through the coil th

Mademuasel [1]

Explanation:

Formula for steady flow energy equation for the flow of fluid is as follows.

$m[h_{1} + \frac{V^{2}_{1}}{2}] + z_{1}g] + q = m[h_{1} + \frac{V^{2}_{1}}{2} + z_{1}g] + w$

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