Answer:
The value is 
Explanation:
From the question we are told that
The mass of the object is 
The unstressed length of the string is 
The length of the spring when it is at equilibrium is 
The initial speed (maximum speed)of the spring when given a downward blow 
Generally the maximum speed of the spring is mathematically represented as

Here A is maximum height above the floor (i.e the maximum amplitude)
and
is the angular frequency which is mathematically represented as

So

=> 
Gnerally the length of the compression(Here an assumption that the spring was compressed to the ground by the hammer is made) by the hammer is mathematically represented as

=> 
=> 
Generally at equilibrium position the net force acting on the spring is

=> 
=> 
So

=> 
Answer:
The mass of 0.02 m³ of gold is 386 kilograms
Explanation:
Given:
The density of the gold = 19300 kg/m³.
The volume of gold = 0.02 m³
To Find:
The mass of gold = ?
Solution:
We know that density is mass divided per unit volume.
Thus mathematically
Density = \frac{mass}{volume}Density=
volume
mass
Rewriting in terms of mass ,
Mass = density * volume
On substituting the known values
Mass = 19300 kg/m³ * 0.02 m³
Mass = 386 kilograms
Learn more about Mass and Density:
Mass=?,volume=190,density=4
Mass 350 kg volume 175 density ans
This is not my answer I copied it but hope it helps:)
Answer:
I'm not sure if I know whatever the answer is
Answer:
The “terminal speed” of the ball bearing is 5.609 m/s
Explanation:
Radius of the steel ball R = 2.40 mm
Viscosity of honey η = 6.0 Pa/s



While calculating the terminal speed in liquids where density is high the stokes law is used for viscous force and buoyant force is taken into consideration for effective weight of the object. So the expression for terminal speed (Vt)

Substitute the given values to find "terminal speed"




The “terminal speed” of the ball bearing is 5.609 m/s
Answer:
16.2 s
Explanation:
Given:
Δx = 525 m
v₀ = 0 m/s
a = 4.00 m/s²
Find: t
Δx = v₀ t + ½ at²
525 m = (0 m/s) t + ½ (4.00 m/s²) t²
t = 16.2 s