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Cerrena [4.2K]
3 years ago
9

Explain the impact that changing pressure has on a system in a state of dynamic equilibrium. What will happen when pressure on a

reaction mixture at equilibrium and with fewer moles on the reactant side is increased?
Chemistry
1 answer:
Gelneren [198K]3 years ago
7 0

Answer:

The reverse direction is favored; formation of reactants.

Explanation:

Hello,

In this case, when the chemical reactions are being carried out in gaseous phase, the pressure has a significant effect if the number of moles of reactants differ from those of the products favoring the equilibrium towards the direction having the fewer amount of moles.

In such a way, if the moles of the reactants are less than those of products, increasing the pressure will reverse the reaction towards reactants again as equilibrium shall be reestablished.

Best regards.

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Calculate the mass of water produced when 5.87 g of butane reacts<br> with excess oxygen.
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Answer:

Explanation:

no. of moles of butane = 5.87g / 58.124 = 0.1009mol

since O2 is excess, limiting reagent is butane

from the equation, 2 moles of butane will reacted to produce water = 10 moles

therefore, 0.1009 moles of butane produced water = (0.1009 x 5) = 0.5050 moles

Weight of H2O formed = 0.5050 x 18.015 = 9.10 grams

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3 years ago
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7 0
3 years ago
Explain the solute and the solvent in a solution
romanna [79]

Answer:

a solute is a substance that is dissolved in the solvent (liquid)

a solvent is a substance that dissolves a solute (solid)

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The Peruvian area of the jungle, living in the high trees is the monkey's habitat.

(I'm not fully sure what a niche is) but:

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3 years ago
A 255 mL round--bonom flask is weighed and found to have a mass of 114.85 g. A few millimeters of an easily vaporized liquid are
Alex17521 [72]

Answer: Option (d) is the correct answer.

Explanation:

According to the given situation, mass of compound will be calculated as follows.

Mass of compound = mass of flask and condensed vapor - mass of flask

                                 = 115.23 - 114.85

                                = 0.38 g

Volume (V) = 255 mL = 255 \times 10^{-6} m^{3}        (as 1 ml = 10^{-6} m^{3})

Pressure (P) = 101325 Pa

Temperature = 100^{o}C = (100 + 273) K = 373 K

Now, according to the ideal gas equation, PV = nRT

and, moles of compound n = \frac{PV}{RT}

                     = \frac{101325 \times 255 \times 10^{-6}}{8.314 \times 373}

                     = 0.008332 mol

As, molar mass of compound = \frac{mass}{\text{no. of moles}}

                                                  = \frac{0.38}{0.008332}

                                                  = 46 g/mol

Therefore, the compound is C_{2}H_{5}OH (molar mass = 12 x 2 + 5 x 1 + 16 + 1 = 46 g/mol).

Thus, we can conclude that out of the given options the liquid could be C_{2}H_{5}OH.  

4 0
3 years ago
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