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Cerrena [4.2K]
3 years ago
9

Explain the impact that changing pressure has on a system in a state of dynamic equilibrium. What will happen when pressure on a

reaction mixture at equilibrium and with fewer moles on the reactant side is increased?
Chemistry
1 answer:
Gelneren [198K]3 years ago
7 0

Answer:

The reverse direction is favored; formation of reactants.

Explanation:

Hello,

In this case, when the chemical reactions are being carried out in gaseous phase, the pressure has a significant effect if the number of moles of reactants differ from those of the products favoring the equilibrium towards the direction having the fewer amount of moles.

In such a way, if the moles of the reactants are less than those of products, increasing the pressure will reverse the reaction towards reactants again as equilibrium shall be reestablished.

Best regards.

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What is the molar concentration of 35 mL of H2SO4 that neutralizes 25 mL of 0.320M NaOH
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V ( H2SO4) = 35 mL / 1000 => 0.035 L

M ( H2SO4) = ?

V ( NaOH ) = 25 mL / 1000 => 0.025 L 

M ( NaOH ) = 0.320 M

number of moles NaOH:

n = M x V

n = 0.025 x 0.320 => 0.008 moles of NaOH

Mole ratio:

<span>2 NaOH + H2SO4 = Na2SO4 + 2 H2O
</span>
2 moles NaOH ---------------------- 1 mole H2SO4
0.008 moles moles NaOH ---------- ??

0.008 x 1 / 2 => 0.004 moles of H2SO4 :

Therefore:

M ( H2SO4) = n / V

M = 0.004 /  0.035

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hope this helps!



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3 years ago
A 26.08 g mixture of zinc and sodium is reacted with a stoichiometric amount of sulfuric acid. The reaction mixture is then reac
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Answer:

Molar percent of sodium in original mixture is 88,50%

Explanation:

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As the amount of BaCl₂ is the maximum possible to produce BaSO₄, the moles of BaCl₂ must be the same than moles of Na₂SO₄.

0,502 moles of BaCl₂ ≡ 0,502 moles of Na₂SO₄

These moles of Na₂SO₄ comes from:

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As the reaction is in stoichiometric amounts, moles of Na are twice the moles of Na₂SO₄

0,502 moles of Na₂SO₄ ×\frac{2molesNa}{1moleNa_{2}SO_{4}}× 22,99 g/mole = 23,08 g of Na

Molar percent of sodium in original mixture is:

\frac{23,08g}{26,08g}*100 = <em>88,50% </em>

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