The empirical formula of this compound is
<u>Given the following data:</u>
<u>Scientific data:</u>
- Molar mass of hydrogen (H) = 1.0 g/mol.
- Molar mass of sulfur (S) = 32 g/mol.
- Molar mass of oxygen (O) = 16 g/mol.
To determine the empirical formula of this compound:
Note: We would assume that the mass of the compound is 100 grams.
Hence, the mass of its constituent elements are:
- Mass of hydrogen (H) = 2.00 grams
- Mass of sulfur (S) = 32.7 grams
- Mass of oxygen (O) = 65.3 grams
Next, we would determine the number of moles of each element by using this formula:
<u>For </u><u>hydrogen</u><u> (</u><u>H</u><u>):</u>
Number of moles = 2.0 moles
<u>For </u><u>sulfur</u><u> (</u><u>S</u><u>):</u>
Number of moles = 1.0 moles
<u>For </u><u>oxygen</u><u> (</u><u>O</u><u>):</u>
Number of moles = 4.0 moles
Empirical formula =
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You did not include the list but F is fluorine. The first halogen.
So, you can expect that the other members of the same group (halogens, column 17 of the periodic table) exhibit similar chemical behavior (reactivity).
So, I am sure your list contains one or more of theses elements: Cl (chlorine), Br (bromine), and I (iodine).
All of them you can expect to also be reactive non metal.
One aluminum atom will cost 0.84 × 10⁻²³ cents.
Explanation:
Aluminium costs 85 cents per 453.592 grams.
number of moles = mass / atomic weight
number of moles of aluminium = 453.592 / 27 = 16.8 moles
To calculate the number of aluminum atoms we use the Avogadro's number:
if 1 mole of aluminum contains 6.022 × 10²³ aluminum atoms
then 16.8 moles of aluminum contains X aluminum atoms
X = (16.8 × 6.022 × 10²³) / 1 = 101.17 × 10²³ aluminum atoms
Now, taking in account the aluminium price, we devise the following reasoning:
if 101.17 × 10²³ aluminum atoms costs 85 cents
then 1 aluminum atom costs Y cents
Y = (1 × 85) / (101.17 × 10²³) = 0.84 × 10⁻²³ cents
Learn more about:
Avogadro's number
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Answer:
Ok so, I think I have it, but it might not be right, but 16 grams of oxygen
Explanation:
2H+O=H2O
36gH2O x 1mol/18g(molar mass of water)= 2 moles of water
20 grams of H2 x 1/2= 10 moles of H2
2 moles of H2 react with 1 mole of O2 to produce 2 moles of water, so...
1 mole O2 x 16g/mole = 16 g O2
the answer to you question is Argon