Answer:
The answer to your question is: Neutral
Explanation:
A neutral solution is a solution whose pH is 7.
That means that this solution has the same amount of H⁺ and OH⁻.
Examples of neutral solutions:
- distilled water
- sugar solution
- table salt
- cooking oil.
Answer:
Option C = 4.25 g
Explanation:
Ounce and grams are unit of mass. Ounce is larger unit while gram is smaller unit. The one ounce is consist of 28.35 g or we can say that one ounce is equal to 28.35 g. In order to convert the given ounce value into grams the value is multiply with 28.35 g.
Given data:
Mass = 0.15 ounce
Mass in gram = ?
Solution:
One ounce is equal to 28.35 g, so
0.15 × 28.35 = 4.25 g
The development of chloroplast is thought to occur through endosymbiosis.
According to the endosymbiosis, some of the organelles found in modern eukaryotic cells, such as mitochondria and chloroplasts, were previously prokaryotic microorganisms. A non-photosynthetic creature acquired one photosynthetic cell, and the chloroplast was subsequently created.
An organelle known as a chloroplast is crucial to the process of photosynthesis in plants. It contains pigments like chlorophyll and other pigments that are in charge of capturing sunlight. Since each chloroplast has two membranes, other organelles such as mitochondria are referred to as double-membrane organelles. It is believed that cyanobacterial endosymbiosis played a role in the genesis of the chloroplast. Prokaryotic organisms like cyanobacteria have the capacity to prepare their food through the process of photosynthesis.
Learn more about endosymbiosis here:
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Answer:
c. Boundary where air masses meet and cold air rises above warm air.
Explanation:
Answer:
see explaination
Explanation:
We are given the (R)-3-bromo-2,3-dimethylpentane and asking to draw the curved arrow which is the showing the mechanism for first-order substitution and first-order elimination reactions. We know the formation of carbocation is the rate determining step in the first-order substitution and first-order elimination reactions.
So in the (R)-3-bromo-2,3-dimethylpentane there is –Br gets removed and formed the tertiary carbocation which is more stable, so the curved arrows in Box 1 to depict the flow of electrons and intermediate in Box 2.
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