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ElenaW [278]
3 years ago
5

Polar and non polar covalent bonds

Chemistry
1 answer:
Hunter-Best [27]3 years ago
4 0
Sorry I didn’t get the answer
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La densidad del óxido de magnesio. MgO, es de 3.581 g/cm3 El MgO, es de 3.581 g/cm3 El MgO cristaliza con ordenamiento cúbico co
Jobisdone [24]

Answer:

a=4.213cm

r=1.490x10^{-8}cm

Explanation:

Hola.

En este caso, para calcular la longitud (a) de una cara de celda unitaria, consideramos la siguiente ecuación:

\rho =\frac{#at*M}{a^3N_A}

En la que consideramos el número de átomos por celda (4 para FCC), la masa molar (40.3 g/mol para MgO) y el número de avogadro para obtener:

3.581g/mol = \frac{4atom/celda*40.3g/mol}{a^3*6.02x10^{23}atom/mol}

Despejando para a, obtenemos:

a^3 = \frac{4atom/celda*40.3g/mol}{3.581g/cm^3*6.02x10^{23}atom/mol}\\\\a=\sqrt[3]{7.478cm^3} \\\\a=4.213cm

Finalmente, el radio lo calculamos como:

r=\frac{\sqrt{2}*a}{4}=\frac{\sqrt{2}*4.213x10^{-8}cm}{4}\\\\r=1.490x10^{-8}cm

¡Saludos!

6 0
4 years ago
A piece of wood has a volume of 30 cm³. It has a length of 2 cm and a width of 3 cm. What is the height of the wood? 5 cm 6 cm 1
Ann [662]
Volume = length × width × height
30 = 2 × 3 × h
30 = 6h
5=h
It is 5 cm high
5 0
4 years ago
Read 2 more answers
The center on your school’s basketball team is 6 ft 10 in tall. How tall is the player in millimeters (mm)?
svp [43]

The answer is 6 ft 10 inches in millimeters (mm) is 0.833 ft.

Given,

The center of the school's basketball team is 6 ft 10 inches tall.

We have to convert the height of the player from feet and inches to feet.

Using the conversion factor,

1 ft = 12 inches

or, 12inches/ 1 ft

Converting 6ft 10 inches to ft, we get;

10 inches × 1 ft/ 12inches

= 0.833 ft

Therefore 6 ft 10 inches in millimeters (mm) is 0.833 ft.

Unit conversion is a method in which we multiply or divide with a particular numerical factor and then finally round off to the nearest significant digits.

To learn more about Millimeter and Unit conversions, visit: brainly.com/question/26371870

#SPJ4

5 0
2 years ago
Tris base has a molecular weight of 121 g/mol. How many grams of tris base would you need to make 250ml of a 200mM SOLUTION
STatiana [176]

Answer:

6.05 g

Explanation:

Molarity of a substance , is the number of moles present in a liter of solution .

M = n / V

M = molarity

V = volume of solution in liter ,

n = moles of solute ,

From the question ,

M = 200mM

Since,

1 mM = 10⁻³ M

M = 200 * 10⁻³ M

V = 250 mL

Since,

1 mL = 10⁻³ L

V = 250 * 10⁻³ L

The moles can be calculated , by using the above relation,

M = n / V  

Putting the respective values ,

200 * 10⁻³ M = n / 250 * 10⁻³ L

n = 0.05 mol

Moles is denoted by given mass divided by the molecular mass ,

Hence ,

n = w / m

n = moles ,

w = given mass ,

m = molecular mass .

From the question ,

m = 121 g/mol

n = 0.05 mol ( calculated above )

The mass of tri base can be calculated by using the above equation ,

n = w / m  

Putting the respective values ,

0.05 mol = w / 121 g/mol

w = 0.05 mol * 121 g/mol

w = 6.05 g

3 0
4 years ago
Read 2 more answers
A compound consists of 75% magnesium and 25% oxygen. Find the empirical formula.
laila [671]
<h2>Answer:</h2>

% Composition of elements:

  • Magnesium = 75%
  • Oxygen = 25%

Atomic mass of given elements:

  • Magnesium = 24 g
  • Oxygen = 16 g

Now, divide % composition by Atomic mass:

\footnotesize\implies Mg = \dfrac{\% \:  Composition}{Atomic  \: mass} =  \dfrac{75}{24}  =  \bf 3.125

\footnotesize\implies O = \dfrac{\% \:  Composition}{Atomic  \: mass} =  \dfrac{25}{16}  =  \bf 1.5625

Simplest Ratio:

\footnotesize\implies Mg  =  \dfrac{3.125}{1.5625}  = 2

\footnotesize\implies O  =  \dfrac{1.5625}{1.5625} = 1

Empirical Formula:

\footnotesize\implies \underline{ \boxed{ \red{ \bf Empirical \:  Formula = Mg_2O}}}

8 0
3 years ago
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