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hoa [83]
3 years ago
6

How does newtons law of the universal gravitation help scientist describe the universe

Physics
2 answers:
Afina-wow [57]3 years ago
5 0
You need to know everything is made of atoms they are always colliding and they are never still because you'd think that every thing in space is still all the time even if it's not making visibly
Bumek [7]3 years ago
5 0
It starts to explain how the solar system stays "together" so to speak, and how the solar system fits into the Milky Way galaxy, and how the galaxies fit together to make a universe of galaxies.
It does this through the idea of the universal force of gravitational attraction (always attractive in N's case) saying that it depends on the masses of the objects concerned, their separation, and a universal gravity constant called G (different from g which is the acceleration of gravity about 10m/s^2)
F=Gm1m2/r^2 is the (inverse square law) force and it applies to all bodies in the universe. 

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Jonah rode his skateboard 350 meters down a straight road at a constant velocity. He skated
Marysya12 [62]

Answer:

250 m/min down the road

Explanation:

Velocity is equivalent to speed but it considers the direction of the object. Velocity is also calculated by dividing the distance travelled by time. Therefore, v=\frac {d}{t} where d and t are distance and time respectively. Given that d is given as 350 m and t is 1.4 s then by substitution v=\frac {350}{1.4}=250 m/min and the direction is down the road.

Velocity is 250 m/min down the road

8 1
3 years ago
30 km/h is _________m/s?<br> A.)8.3<br> B.)5.6<br> C.)13.9<br> D.)11.1
Juli2301 [7.4K]

Answer:

Correct  Option :-  A

Explanation:

3 0
2 years ago
What is the speed of the tip of the minute hand of a clock where the hand is of length 7cm?​
azamat

Explanation:

Q1) What is the speed of the tip of the minute hand of a clock where the hand is of length 7cm?

Ans1) speed, v=st=2πrT=2×227×7×10-260×60=119×10-4=1.22×10-4m/s

<h2><em><u>Hope it helps</u></em></h2>
5 0
3 years ago
Question 18 according to newton's second law of motion, the force acting on an object varies directly with the object's accelera
leonid [27]
Solve for "x"
X=force
18/6=x/9
cross multiply 
162=6x
x=27
Hope this helps
3 0
3 years ago
An object, whose mass is 0.660 kg, is attached to a spring with a force constant of 132 N/m. The object rests upon a frictionles
Arada [10]

Answer:

See below

Explanation:

a)  Spring force at release =  k * d = 132 N/m * .120 m = 15.84 N

b) F = ma

   15.84 = (.660 kg)(a)     a = 24 m/s^2

c) Toward the left ....the object is accelerated to the left

7 0
1 year ago
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