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4 years ago

When a conducting plate swings through a magnetic field, which is true?

Physics

2 answers:

Nookie1986 [14]4 years ago

7 0

Answer:

Energy is transferred from mechanical energy to thermal energy. (A)

Explanation:

As the conducting plate is swinging, we know it posseses some form of mechanical energy (either K or U). Because the plate is conducting, charge is transfered, yielding energy transfer to thermal.

VLD [36.1K]4 years ago

4 0

Answer:

Energy is transferred from mechanical energy to thermal energy and then back to mechanical energy ( D )

Explanation:

when conducting plate swings through a magnetic field, energy is transferred from mechanical energy to thermal energy and then back to mechanical energy and this is due to the induction of eddy currents during the process of that the conducting plate swings through the magnetic field.

An eddy current is induced in conductor when the magnetic field in which the conductor is located varies.

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If you drop an object, it accelerates downward at 9.8 m/s2 (in the absence of air resistance). If, instead, you throw it downwar

Korvikt [17]

If you drop an object, it accelerates downward at 9.8 m/s2 (in the absence of air resistance). If instead, you throw it downward, its downward acceleration after release is 9.8 m/s2.

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities and accelerations. The direction of the net force acting on an object determines the direction of its acceleration. Uniform acceleration, non-uniform acceleration, and average acceleration are the three different forms of accelerated motions.

A free-falling object experiences a downward acceleration of 9.8 m/s/s (on Earth). This specific designation is given to the numerical value for an object in free fall because it is such an essential value. The longer an object is in free fall, the faster it descends toward the ground due to gravity. In actuality, an object's velocity rises by 9.8 m/s2, so it reaches 9.8 m/s by the time it begins to fall.

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2 years ago

What is defined as a material resistance to the transmission of light waves flashcards?

seraphim [82]

This property is called "Opacity".

The question is worded in a difficult way. A more easily understood wording of this question would be:

"<em>What is the name of the property of a material that prevents light passing through?"</em>

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3 years ago

A region of space in which a test charge experiences a force is referred to as

Alecsey [184]

Answer: The correct answer is- Field.

Explanation -

The modified space around a charged particle is known as electric field.

The strength of electric field at a point is calculated as the force experienced by a unit test charge present at that point.

Thus, a region of space in which a test charge experiences a force is referred to as Field.

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3 years ago

Read 2 more answers

Cars A and B are racing each other along the same straight road in the following manner: Car A has a head start and is a distanc

4vir4ik [10]

The question is incomplete. Here is the complete question.

Cars A nad B are racing each other along the same straight road in the following manner: Car A has a head start and is a distance $D_{A}$ beyond the starting line at t = 0. The starting line is at x = 0. Car A travels at a constant speed $v_{A}$ . Car B starts at the starting line but has a better engine than Car A and thus Car B travels at a constant speed $v_{B}$ , which is greater than $v_{A}$ .

Part A: How long after Car B started the race will Car B catch up with Car A? Express the time in terms of given quantities.

Part B: How far from Car B's starting line will the cars be when Car B passes Car A? Express your answer in terms of known quantities.

Answer: Part A: $t=\frac{D_{A}}{v_{B}-v_{A}}$

Part B: $x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}$

Explanation: First, let's write an equation of motion for each car.

Both cars travels with constant speed. So, they are an uniform rectilinear motion and its position equation is of the form:

$x=x_{0}+vt$

where

$x_{0}$ is initial position

v is velocity

t is time

Car A started the race at a distance. So at t = 0, initial position is $D_{A}$ .

The equation will be:

$x_{A}=D_{A}+v_{A}t$

Car B started at the starting line. So, its equation is

$x_{B}=v_{B}t$

Part A: When they meet, both car are at "the same position":

$D_{A}+v_{A}t=v_{B}t$

$v_{B}t-v_{A}t=D_{A}$

$t(v_{B}-v_{A})=D_{A}$

$t=\frac{D_{A}}{v_{B}-v_{A}}$

Car B meet with Car A after $t=\frac{D_{A}}{v_{B}-v_{A}}$ units of time.

Part B: With the meeting time, we can determine the position they will be:

$x_{B}=v_{B}(\frac{D_{A}}{v_{B}-v_{A}} )$

$x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}$

Since Car B started at the starting line, the distance Car B will be when it passes Car A is $x_{B}=\frac{v_{B}D_{A}}{v_{B}-v_{A}}$ units of distance.

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3 years ago

Which marine habitats would have the least access to primary producers?

nikitadnepr [17]

Answer:

Explanation:

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2 years ago