Write the repeating decimal 0.515151515151... as a fully simplified fraction.

Mathematics

2 answers:

mote1985 [20]3 years ago

7 0

<h3>Answer: 51/99</h3>

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Work Shown:

x = 0.515151...

100x = 51.515151....

Subtract the two equations to get 100x-x = 99x on the left side and 51.515151.... - 0.515151... = 51 on the right side. Notice the decimal portions cancel out.

So we end up with 99x = 51 which solves to x = 51/99

This means 51/99 = 0.515151...

sveticcg [70]3 years ago

4 0

Answer:

17/33

Step-by-step explanation:

We first let 0.51 be x.

Since x is recurring in 2 decimal places, we multiply it by 100.

100x=51.51

Next, we subtract them.

100x−x=51.51−0.51

99x=51

Lastly, we divide both sides by 99 to get x as a fraction.

x=51/99

=17/33

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A 12,000-lb killer whale might eat as much as 14,000 lb of fish per month (assume a 30-day month). If the average weight of a ce

brilliants [131]

Answer:

2196 fish

Step-by-step explanation:

Weight of fish that the killer whale might eat in a month (30 days) = 14,000 lb

Weight of the fish that killer whale might eat in a day = $\frac{14000}{30} = \frac{1400}{3}$ lb.

Average weight of the fish that killer whale eats = 3.4 oz

Since,

1 pound(lb) = 16 ounces(oz)

So,

Weight of the fish that killer whale might eat in a day in ounces(oz) = $\frac{1400}{3} \times 16=\frac{22400}{3}$ oz

Since, a certain fish weighs 3.4 oz, in order to find the number of fish that killer whale must eat, we must divide the total weight in ounces by 3.4 ounces.

So, the number of fish that killer whale would eat = $\frac{22400}{3} \div 3.4 = 2196$ fish