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djyliett [7]
3 years ago
8

What is the specific heat of a 75.01 g piece of an unknown metal that exhibits a 45.2°C temperature change upon absorbing 1870 J

of heat?
Chemistry
1 answer:
mariarad [96]3 years ago
8 0

Answer:

Cp=0.552\frac{J}{g\°C}

Explanation:

Hello,

In this case, the formula to compute the required heat based on the mass, specific heat and change in temperature is widely known as:

Q=mCp\Delta T

In such a way, since we are asked to compute the specific heat, we solve for it as shown below:

Cp=\frac{Q}{m\Delta T}=\frac{1870J}{75.01g*45.2\°C} \\ \\Cp=0.552\frac{J}{g\°C}

Best regards.

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Tamiku [17]

Answer:

Here's what I get.

Explanation:

Ba is element 56. Its electron configuration is

1s² 2s²2p⁶ 3s²3p⁶ 4s²3d¹⁰4p⁶ 5s²4d¹⁰5p⁶ 6s²

That's a lot of writing.

To lessen the work, chemists have developed the noble gas notation.

The core electrons of Ba (listed in boldface) have the same electron configuration as Xe, the noble gas found two atoms earlier in the Periodic Table.

Chemists replace the core electron configuration with the symbol of the corresponding noble gas.

The noble gas notation for Ba becomes

Ba: [Xe]6s².

5 0
3 years ago
most radioactive atoms “spontaneously” decay to a more stable form. where does the “additional” energy go once the atoms have de
blsea [12.9K]

When most radioactive atoms “spontaneously” decay to a more stable form the “additional” energy is converted to radiation with the emission of radioactive particles.

<h3>What is radioactivity?</h3>

Radioactivity is the spontaneous decay of the nucleus of an atom with the emission of radiation and nuclear particles.

Elements that spontaneously decay are called radioactive elements.

When these radioactive elements decay, they form more stable isotopes or elements.

The spontaneous decay of atoms of radioactive elements is in order for the nucleus of the atom to become stable and non-radioactive.

Learn more about radioactivity at:

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4 0
10 months ago
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