Question

What is the specific heat of a 75.01 g piece of an unknown metal that exhibits a 45.2°C temperature change upon absorbing 1870 J of heat?

Answer 1

Answer:

$Cp=0.552\frac{J}{g\°C}$

Explanation:

Hello,

In this case, the formula to compute the required heat based on the mass, specific heat and change in temperature is widely known as:

$Q=mCp\Delta T$

In such a way, since we are asked to compute the specific heat, we solve for it as shown below:

$Cp=\frac{Q}{m\Delta T}=\frac{1870J}{75.01g*45.2\°C} \\ \\Cp=0.552\frac{J}{g\°C}$

Best regards.