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Vika [28.1K]
3 years ago
7

If 10ml of 1.00M HCI(aq) neutralized 30 ml of an NaOH solution. What was the molarity of the Na OH solution?​

Chemistry
2 answers:
s2008m [1.1K]3 years ago
8 0
First, figure out the balanced equation:
HCl + NaOH -> NaCl + H2O (already balanced)
Now, convert the milliliters to liters since molarity is moles/liters
10 ml = 0.01 L
30 ml = 0.03 L
Now, set up the equation and type this into the calculator:
(0.01 L HCl) x (1.00 mol HCl) x (1 mol NaOH) x (1)/ (1) x (1 L HCl) x (1 mol HCl) x (0.03 L NaOH)
This should equal 0.333333 mol/L or M of NaOH

Ahat [919]3 years ago
6 0

Explanation:

plz mark as brainlist///////

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A. is the correct answer.
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Which equation shows how to calculate how many grams (g) of KOH would be needed to fully react with 4 mol Mg(OH)2? The balanced
bazaltina [42]
Mole ratio:

MgCl₂ + 2 KOH = Mg(OH)₂ + 2 KCl

2 moles KOH ---------------- 1 mole Mg(OH)₂
moles KOH ------------------- 4 moles Mg(OH₂)

moles KOH = 4 x 2 / 1

= 8 moles of  KOH

molar mass KOH = 56 g/mol

mass of KOH = n x mm

mass of  KOH = 8 x 56

= 448 g of KOH 

hope this helps!

3 0
3 years ago
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The following reaction has an equilibrium constant (Keq) of 1 under standard conditions and can be catalysed by the enzyme aspar
Trava [24]

Answer:

  1. What is the AGⓇ of this reaction? 0.
  2. Which will be favoured - the forward reaction, the reverse reaction, or neither? Neither.
  3. What effect does the presence of the enzyme aspartate transaminase have on the Key value when compared with its value in the absence of enzyme? It does not affect the value of Keq.
  4. If one of the products of reaction 1, oxaloacetate, is removed by converting it to citrate as follows: Reaction 2: oxaloacetate + acetyl-CoA citrate + COASH will the key for Reaction l be changed? No, the Keq does not change.

Explanation:

1. To calculate the delta G of a reaction given the K, we use the following equation:

ΔG°= -RT ln K.

Which gives us 0 when K is 1.

2.None of the reactions is favoured. Given that the K equals 1, the system will try to keep the concentration of both products and reagents the same.

3. A catalyst is a substance that, when added, provides a different and faster mechanism through which a reaction takes place. This only means that the speed at which the equilibrium is attained is reduced, but the enzyme does nothing to alter the difference in energy (ΔG°) of the start and end points of the reaction, which ultimately gives us the value of Keq.

4. The addition of a side reaction does not change the value of Keq for the main reaction. They are both separate ways of making oxaloacetate disappear. While the Keq does not change, keep in mind that the end concentrations will not be the same, for any set of starting concentrations of your substances.

4 0
3 years ago
Balance this equation. Not all spots have to have a number.
Lisa [10]

2Na+2H2O----2NaOH+H2

3 0
3 years ago
4) The most electronegative atom of the ones listed below is ____.AlBTlInGa
marusya05 [52]

Answer:

B

Explanation:

Here, we wnat to get the most electronegative atom

On the periodic table, electronegativity increases across a period and decrease down the group

The elements listed are in the same group

Boron is the first member of the group

Boron is the most electronegative atom in the group

5 0
1 year ago
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