Question

If 10ml of 1.00M HCI(aq) neutralized 30 ml of an NaOH solution. What was the molarity of the Na OH solution?​

Answer 1

First, figure out the balanced equation:
HCl + NaOH -> NaCl + H2O (already balanced)
Now, convert the milliliters to liters since molarity is moles/liters
10 ml = 0.01 L
30 ml = 0.03 L
Now, set up the equation and type this into the calculator:
(0.01 L HCl) x (1.00 mol HCl) x (1 mol NaOH) x (1)/ (1) x (1 L HCl) x (1 mol HCl) x (0.03 L NaOH)
This should equal 0.333333 mol/L or M of NaOH

Answer 2

Explanation:

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