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melisa1 [442]
4 years ago
5

Recall that the volume V of a sphere of radius r can be computed using the formula. If the radius of a spherical balloon is incr

easing at a rate of 5 cm/min, how fast is its volume increasing when the radius is 10 cm?
Physics
1 answer:
alekssr [168]4 years ago
6 0

Answer:

Explanation:

Given that,

A sphere has a volume of V and a radius r

Volume of sphere cam be determine using the formula

V = 4/3 πr³

V = 4πr³ / 3.

If the radius of the sphere is increasing by

dr / dt = 5cm / min

How fast is the volume increasing when r = 10cm

dV / dt =?

From V = 4πr³ / 3

We can calculate dV/dr

dV/dr = 12πr² / 3

dV/dr = 4πr²

Then,

We want to find dV/dt

Using chain rule

dV/dt = dV/dr × dr / dt

dV/dt = 4πr² × 5

dV/dt = 20πr²

So, at r = 10

dV/dt { 20π × 10²

dV/dt = 6283.19 cm/min

The rate at which the volume increase is 6283.19 cm/min

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The energy conservation and trigonometry we can find the results for the questions about the movement of the acrobat are;

     a) The maximum speed is v = 4.89 m / s

     b) The maximum height is h = 1.22 m

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               Em = K + U

Let's write the energy in two points.

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Let's use trigonometry to find the height, see attached.

         h = L - L cos θ

         h = L (1- cos θ)

They indicate that the initial angle is tea = 48º and the length is L = 3.7 m, let's calculate.

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     a) The maximum speed is v = 4.89 m / s

     b) The maximum height is h = 1.22 m

Learn more here: brainly.com/question/13010190

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