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Readme [11.4K]
3 years ago
11

SOMEONE PRETTY PLEASE FILL THIS OUT Its the ball drop project Lab Report Title: Formulate Hypothesis: What are your independent,

dependent and constant variable? Data and Observations Temperature Height Dropped Bounce Height Ball 1 Ball 2 Ball 3 Temperature Height Dropped Bounce Height Ball 1 : Ball 2: Ball 3: Discussion and Conclusions Type your discussion and conclusions here.
Physics
1 answer:
Tatiana [17]3 years ago
5 0
Please help me tooooornrjjfjenr
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Dina has a mass of 50 kilograms and is waiting at the top of a ski slope that’s 5.0 meters high.
Over [174]
All of Dina's potential energy Ep is converted into kinetic energy Ek so Ep=Ek, where Ep=m*g*h and Ek=(1/2)*m*v². m is the mass of Dina, h is the height of ski slope, g=9.8 m/s² and v is the maximal velocity. 

So we solve for v:

m*g*h=(1/2)*m*v², masses cancel out,

g*h=(1/2)*v², we multiply by 2,

2*g*h=v² and take the square root to get v

√(2*g*h)=v, we plug in the numbers and get:

v=9.9 m/s. 

So Dina's maximum velocity on the bottom of the ski slope is v=9.9 m/s.
8 0
2 years ago
Read 2 more answers
What is the magnitude of the electric field on a +2 C charge if it experiences an electric force of 6 N?
MrMuchimi

Answer:

call me 7164013838 hurry bye

6 0
2 years ago
A car slows down from 27.7 m/s <br> to 10.9 m/s in 2.37 s. <br> What is its acceleration?
Sunny_sXe [5.5K]

Answer:

- 7.088 m/s²

Explanation:

As we know that,

★ Acceleration = Change in velocity/Time

→ a = (v - u)/t

Here,

  • Initial velocity (u) = 27.7 m/s
  • Final velocity (v) = 10.9 m/s

→ a = (10.9 m/s - 27.7 m/s)/2.37 s

→ a = -16.8/2.37 m/s²

→ <u>a</u><u> </u><u>=</u><u> </u><u>-</u><u>7</u><u>.</u><u>0</u><u>8</u><u>8</u><u> </u><u>m/s²</u> [Answer]

Negative sign denotes that the velocity is decreasing.

4 0
3 years ago
Read 2 more answers
A car traveled north 25 km for 1 hour. The car’s SPEED is 25 km/hr north.
kramer

Answer:

hgk

Explanation:

6 0
3 years ago
The 5-kg block A has an initial speed of 5 m/s as it slides down the smooth ramp, after which it collides with the stationary bl
Akimi4 [234]

Answer:

The coupled velocity of both the blocks is 1.92 m/s.

Explanation:

Given that,

Mass of block A, m_1=5\ kg

Initial speed of block A, u_1=5\ m/s

Mass of block B, m_2=8\ kg

Initial speed of block B, u_2=0

It is mentioned that if the two blocks couple together after collision. We need to find the common velocity immediately after collision. We know that due to coupling, it becomes the case of inelastic collision. Using the conservation of linear momentum. Let V is the coupled velocity of both the blocks. So,

m_1u_1+m_2u_2=(m_1+m_2)V\\\\V=\dfrac{m_1u_1+m_2u_2}{(m_1+m_2)}\\\\V=\dfrac{5\times 5+0}{(5+8)}\\\\V=1.92\ m/s

So, the coupled velocity of both the blocks is 1.92 m/s. Hence, this is the required solution.

8 0
3 years ago
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