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mrs_skeptik [129]
3 years ago
11

What does the person in back of the ambulance experience? A) a lower frequency of the siren B) a lower amplitude of the siren C)

a higher frequency of the siren Eliminate D) a higher amplitude of the siren
Physics
2 answers:
hoa [83]3 years ago
5 0

The answer to your question is "A. a lower frequency of the siren.

Because the person in back of the ambulance will hear a lower frequency of the siren. This is because the waves are stretched out. A longer wavelength results in a lower frequency.

denpristay [2]3 years ago
4 0

Answer: The correct answer is A.

Explanation:

When there is a relative motion between the source and the observer then there will be change in the frequency or wavelength of the wave. This phenomenon is called Doppler effect.

For example, when the source and the observer are moving away from other then the frequency decreases in this case.

In the given problem, the person is in the back of the ambulance. In this case, the person in the back of the ambulance will listen a lower frequency of the wave. There will be longer wavelength.

Therefore, the correct answer is A.

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An electronic line judge camera captures the impact of a 57.0-g tennis ball traveling at 32.2 m/s with the side line of a tennis
mote1985 [20]

Answer:

average acceleration is 1.365 × 10^{4} m/s²

Explanation:

given data

initila speed  u = -32.2 m/s

final speed v = 21.6 m/s

time taken t = 0.00394 s

solution

we get here average acceleration that will be express as

v = u + at    ..........................1

put here value and we get

21.6 = -32.2 + a × 0.00394

solve it we get

a = 1.365 × 10^{4} m/s²

so average acceleration is 1.365 × 10^{4} m/s²

3 0
3 years ago
1.si un automovil de 3000 kg se desplaza a 40 m/s su energía cinética es igual a
Mila [183]
The answer for this is b 3.500.000j
6 0
2 years ago
Which of two factors influence the weight of an object due to gravitational pull?
densk [106]
The weight of an object when calculated by multiplying with the pull of the gravity is dependent on the mass of the object and the value of g. The value of g is constant however is still dependent on the distance of the object from the center of the Earth. Thus, the answers are <em>mass and distance. </em>
5 0
3 years ago
Where must an object be placed to form an image 30.0 cm from a diverging lens with a focal length of 43.0 cm?
Schach [20]
Using lens equation;

1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)

Substituting;

1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm

Therefore, the object should be place 99.23 cm from the lens.
6 0
3 years ago
The particle, initially at rest, is acted upon only by the electric force and moves from point a to point b along the x axis, in
bezimeni [28]

1) Potential difference: 1 V

2) V_b-V_a = -1 V

Explanation:

1)

When a charge moves in an electric field, its electric potential energy is entirely converted into kinetic energy; this change in electric potential energy is given by

\Delta U=q\Delta V

where

q is the charge's magnitude

\Delta V is the potential difference between the initial and final position

In this problem, we have:

q=4.80\cdot 10^{-19}Cis the magnitude of the charge

\Delta U = 4.80\cdot 10^{-19}J is the change in kinetic energy of the particle

Therefore, the potential difference (in magnitude) is

\Delta V=\frac{\Delta U}{q}=\frac{4.80\cdot 10^{-19}}{4.80\cdot 10^{-19}}=1 V

2)

Here we have to evaluate the direction of motion of the particle.

We have the following informations:

- The electric potential increases in the +x direction

- The particle is positively charged and moves from point a to b

Since the particle is positively charged, it means that it is moving from higher potential to lower potential (because a positive charge follows the direction of the electric field, so it moves away from the source of the field)

This means that the final position b of the charge is at lower potential than the initial position a; therefore, the potential difference must be negative:

V_b-V_a = - 1V

8 0
3 years ago
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