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mrs_skeptik [129]
3 years ago
11

What does the person in back of the ambulance experience? A) a lower frequency of the siren B) a lower amplitude of the siren C)

a higher frequency of the siren Eliminate D) a higher amplitude of the siren
Physics
2 answers:
hoa [83]3 years ago
5 0

The answer to your question is "A. a lower frequency of the siren.

Because the person in back of the ambulance will hear a lower frequency of the siren. This is because the waves are stretched out. A longer wavelength results in a lower frequency.

denpristay [2]3 years ago
4 0

Answer: The correct answer is A.

Explanation:

When there is a relative motion between the source and the observer then there will be change in the frequency or wavelength of the wave. This phenomenon is called Doppler effect.

For example, when the source and the observer are moving away from other then the frequency decreases in this case.

In the given problem, the person is in the back of the ambulance. In this case, the person in the back of the ambulance will listen a lower frequency of the wave. There will be longer wavelength.

Therefore, the correct answer is A.

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The Law of Reflection states that the Angle of Incidence will always be
VladimirAG [237]

Answer: option c) equal to the angle of reflection.

HOPE IT HELPS YOU

HAVE A GOOD DAY ❤️☺️

7 0
3 years ago
Gauss's law is usualy written as :
snow_tiger [21]

Answer:

(a) the net charge inside the closed surface.

Explanation:

In Gauss' Law, Qencl refers to the net charge inside the Gaussian surface. This surface is usually taken as a symmetric geometric surface, but this is merely for simplicity. Gauss' Law holds for any closed surface. Inside this surface there can be insulators as well as conductors. Regardless of the geometry or the materials inside, Qencl refers to the net charge inside the closed surface. The charge outside the surface is irrelevant for Gauss' Law, therefore all the charge in the physical system is not included in Gauss' Law.

4 0
3 years ago
Two forces whose resultant is 100N,are perpendicular to each other.if one of them makes an angle of 60° with the resultant, calc
DIA [1.3K]

Magnitude of the force = 50N

<u />

<u>Explanation:</u>

Let one force be X

And the second force be Y

Both the forces are perpendicular, so α = 90°

The resultant R of the two forces = 100N

Angle between resultant and 1 force, α = 60°

We know,

R² = X² + Y² + 2XYcos 90

100² = X² + Y²

If X makes an angle of Φ = 60°

Then, tan Ф =  Y sin α / X + Y cos α

Putting the values we find,

tan 60 = Y/X

Y  = √3X

Putting Y = √3X in equation 1 we get,

(X)² + (√3X)² = 100 X 100

4X² = 100 X 100

X² = 2500

X = 50N

Therefore, magnitude of the force = 50N

5 0
4 years ago
b) The distance of the red supergiant Betelgeuse is approximately 427 light years. If it were to explode as a supernova, it woul
Nat2105 [25]

Answer:

b) Betelgeuse would be \approx 1.43 \cdot 10^{6} times brighter than Sirius

c) Since Betelgeuse brightness from Earth compared to the Sun is \approx 1.37 \cdot 10^{-5} } the statement saying that it would be like a second Sun is incorrect

Explanation:

The start brightness is related to it luminosity thought the following equation:

B = \displaystyle{\frac{L}{4\pi d^2}} (1)

where B is the brightness, L is the star luminosity and d, the distance from the star to the point where the brightness is calculated (measured). Thus:

b) B_{Betelgeuse} = \displaystyle{\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2}} and B_{Sirius} = \displaystyle{\frac{26L_{Sun}}{4\pi (26\ ly)^2}} where L_{Sun} is the Sun luminosity (3.9 x 10^{26} W) but we don't need to know this value for solving the problem. ly is light years.

Finding the ratio between the two brightness we get:

\displaystyle{\frac{B_{Betelgeuse}}{B_{Sirius}}=\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2} \times \frac{4\pi (26\ ly)^2}{26L_{Sun}} \approx 1.43 \cdot 10^{6} }

c) we can do the same as in b) but we need to know the distance from the Sun to the Earth, which is 1.581 \cdot 10^{-5}\ ly. Then

\displaystyle{\frac{B_{Betelgeuse}}{B_{Sun}}=\frac{10^{10}L_{Sun}}{4\pi (427\ ly)^2} \times \frac{4\pi (1.581\cdot 10^{-5}\ ly)^2}{1\ L_{Sun}} \approx 1.37 \cdot 10^{-5} }

Notice that since the star luminosities are given with respect to the Sun luminosity we don't need to use any value a simple states the Sun luminosity as the unit, i.e 1. From this result, it is clear that when Betelgeuse explodes it won't be like having a second Sun, it brightness will be 5 orders of magnitude smaller that our Sun brightness.

4 0
3 years ago
Which atmospheric condition is most likely responsible for the wind blowing the clouds from the sea towards the land?
lions [1.4K]
Uneven heating of land and sea causes warm air over land to rise up, creating a low pressure zone. So wind blows in from the sea to fill this low pressure zone
3 0
3 years ago
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