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kobusy [5.1K]
3 years ago
5

Determine the displacement of a plane that is uniformly accelerated from 66 m/s to 88 m/s in 12 s

Physics
1 answer:
german3 years ago
7 0
Displacement is the area under the graph for velocity-time graph so if plane accelerated uniformly from 66m/s to 88m/s the area will be the area of trapezium where formula for area under trapezium is 1/2 (sum of parallel lines) x height so the parallel lines in this case are 66m/s and 88m/s and height is time taken which is 12 so displacement is 1/2 (66+88)(12)= 924m

if you want to know the formula then it is S=1/2 (V+U)(t) where S is displacement V is final velocity U is initial velocity and t is time taken
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klasskru [66]

Answer:

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Explanation:

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2 years ago
A homodimeric protein was found to migrate through SDS polyacrilamide gel electrophoresis (SDS-PAGE) with a mobility that matche
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Adding a reducing agent

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3 years ago
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Oduvanchick [21]

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5 0
2 years ago
An LED operation at 850 nm center wavelength has a spectral width of 45 nm. What is the pulse spreading in ns/km
Papessa [141]

Answer:

\mathbf{\dfrac{\sigma_{mat}}{L} = 3.6 \ ns/ km}

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\dfrac{\sigma_{mat}}{L} = (80 \ ps/ ( m.km) \ )  \times (45 \ nm)

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3 0
3 years ago
An object accelerates at 32 m/s² when a force of 71 N is applied to it. What is the object’s mass? show your work
amid [387]

Answer:

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6 0
2 years ago
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