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4 years ago

Which pair of quantities includes one quantity that increases as the other decreases during simple harmonic motion?

Physics

2 answers:

11111nata11111 [884]4 years ago

7 0

Kinetic energy and potential energy pair is the quantity in which one will increase then other will decrease

As we know that sum of kinetic energy and potential energy will always remain conserved

So here we will have

$KE + PE = constant$

so here as we move away from mean position the kinetic energy will decrease while at the same time potential energy will increase.

So the pair of potential energy and kinetic energy will satisfy the above condition

nikklg [1K]4 years ago

6 0

The Correct Answer is velocity and displacement.

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Alkaline batteries have the advantage of putting out constant voltage until very nearly the end of their life. How long will an

Sidana [21]

Answer:

Explanation:

Voltage, V = 1.58 V

Power, P = 1 W

1 A.h

Charge, Q = 1 A.h = 1 x 3600 A.s = 3600 C

Power x time = Voltage x charge

1 x t = 1.58 x 3600

t = 1.58 x 3600 second

t = 1.58 hours

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4 years ago

One negative change you may encounter as a student or an employee

matrenka [14]

Answer:

you may get bullied or teased for being a differrent race, ethnic.

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3 years ago

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3 years ago

A 1.50 cm high diamond ring is placed 20.0 cm from a concave mirror with radius of curvature 30.00 cm. The magnification is ____

Rama09 [41]

Answer:

Magnification, m = -0.42

Explanation:

It is given that,

Height of diamond ring, h = 1.5 cm

Object distance, u = -20 cm

Radius of curvature of concave mirror, R = 30 cm

Focal length of mirror, f = R/2 = -15 cm (focal length is negative for concave mirror)

Using mirror's formula :

$\dfrac{1}{f}=\dfrac{1}{u}+\dfrac{1}{v}$ , f = focal length of the mirror

$\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}$

$\dfrac{1}{v}=\dfrac{1}{-15}+\dfrac{1}{-20}$

v = -8.57 cm

The magnification of a mirror is given by,

$m=\dfrac{-v}{u}$

$m=\dfrac{-(-8.57)}{-20}$

m = -0.42

So, the magnification of the concave mirror is 0.42. Thew negative sign shows that the image is inverted.

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4 years ago

A car drives 215 km east and then 45 km north. What is the magnitude of the car’s displacement? Round your answer to the nearest

34kurt

Displacement = (straight-line distance between the start point and end point) .

Since the road east is perpendicular to the road north,
the car drove two legs of a right triangle, and the magnitude
of its final displacement is the hypotenuse of the triangle.

Length of the hypotenuse = √ (215² + 45²)

= √ (46,225 + 2,025)

= √ 48,250

= 219.7 miles .

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3 years ago

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