Answer:
the energy difference between adjacent levels decreases as the quantum number increases
Explanation:
The energy levels of the hydrogen atom are given by the following formula:
![E=-E_0 \frac{1}{n^2}](https://tex.z-dn.net/?f=E%3D-E_0%20%5Cfrac%7B1%7D%7Bn%5E2%7D)
where
is a constant
n is the level number
We can write therefore the energy difference between adjacent levels as
![\Delta E=-13.6 eV (\frac{1}{n^2}-\frac{1}{(n+1)^2})](https://tex.z-dn.net/?f=%5CDelta%20E%3D-13.6%20eV%20%28%5Cfrac%7B1%7D%7Bn%5E2%7D-%5Cfrac%7B1%7D%7B%28n%2B1%29%5E2%7D%29)
We see that this difference decreases as the level number (n) increases. For example, the difference between the levels n=1 and n=2 is
![\Delta E=-13.6 eV(\frac{1}{1^2}-\frac{1}{2^2})=-13.6 eV(1-\frac{1}{4})=-13.6 eV(\frac{3}{4})=-10.2 eV](https://tex.z-dn.net/?f=%5CDelta%20E%3D-13.6%20eV%28%5Cfrac%7B1%7D%7B1%5E2%7D-%5Cfrac%7B1%7D%7B2%5E2%7D%29%3D-13.6%20eV%281-%5Cfrac%7B1%7D%7B4%7D%29%3D-13.6%20eV%28%5Cfrac%7B3%7D%7B4%7D%29%3D-10.2%20eV)
While the difference between the levels n=2 and n=3 is
![\Delta E=-13.6 eV(\frac{1}{2^2}-\frac{1}{3^2})=-13.6 eV(\frac{1}{4}-\frac{1}{9})=-13.6 eV(\frac{5}{36})=-1.9 eV](https://tex.z-dn.net/?f=%5CDelta%20E%3D-13.6%20eV%28%5Cfrac%7B1%7D%7B2%5E2%7D-%5Cfrac%7B1%7D%7B3%5E2%7D%29%3D-13.6%20eV%28%5Cfrac%7B1%7D%7B4%7D-%5Cfrac%7B1%7D%7B9%7D%29%3D-13.6%20eV%28%5Cfrac%7B5%7D%7B36%7D%29%3D-1.9%20eV)
And so on.
So, the energy difference between adjacent levels decreases as the quantum number increases.
The most exact answer is 78.4J also in this kind of options we can say answer "d"
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