Answer:
The acceleration of the proton is 9.353 x 10⁸ m/s²
Explanation:
Given;
speed of the proton, u = 6.5 m/s
magnetic field strength, B = 1.5 T
The force of the proton is given by;
F = ma = qvB(sin90°)
ma = qvB
where;
m is mass of the proton, = 1.67 x 10⁻²⁷ kg
charge of the proton, q = 1.602 x 10⁻¹⁹ C
The acceleration of the proton is given by;
Therefore, the acceleration of the proton is 9.353 x 10⁸ m/s²
Answer:
2.00 m/s²
Explanation:
Given
The Mass of the metal safe, M = 108kg
Pushing force applied by the burglar, F = 534 N
Co-efficient of kinetic friction, = 0.3
Now,
The force against the kinetic friction is given as:
Where,
N = Normal reaction
g= acceleration due to the gravity
Substituting the values in the above equation, we get
or
Now, the net force on to the metal safe is
Substituting the values in the equation we get
or
also,
acceleration of the safe
Therefore, the acceleration of the metal safe will be
acceleration of the safe=
or
acceleration of the safe=
or
acceleration of the safe=
Hence, the acceleration of the metal safe will be 2.00 m/s²