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Vladimir79 [104]
3 years ago
15

How does potential difference behave in a parallel circuit

Physics
2 answers:
Illusion [34]3 years ago
6 0
The same voltage will appear across all resistors in parallel. 
Fudgin [204]3 years ago
3 0
In Parallel circuits, the electric potential difference across each resistor is the same. ... In a parallel circuit, the voltage drops across each of the branches is the same as the voltage gain in the battery. Thus, the voltage drop is the same across each of these resistors. happy to help:)
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A bird takes off from the tree and after 5 s is flying at a speed of 10 m/s. Calculate
Volgvan

Answer:

10miles/second

Explanation:

Change in velocity of the bird is expressed as the difference between the final velocity and initial velocity of the body.

Change in velocity = Final velocity - initial velocity

Since the bird takes off from the tree, the initial velocity of the bird = 0miles/sec

Final velocity = 10miles/secs

Change in velocity = 10-0

Change in velocity = 10miles/second

6 0
2 years ago
A student constructed a series circuit consisting of a 12.0-volt battery, a 10.0-ohm lamp, and a
Stels [109]
The power dissipated across a component can be calculated through the formula P=I^2xR

Substituting the values in we get P=(0.5)^2x10=2.5W
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3 years ago
Which of the fundamental forces explains the structure of atoms and molecules?
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7 0
3 years ago
Read 2 more answers
If the mass of an object increases by a factor 2, kinetic energy?
emmainna [20.7K]

Answer:

A) Increases by a factor of 2

Explanation:

Kinetic energy can be defined as an energy possessed by an object or body due to its motion.

Mathematically, kinetic energy is given by the formula;

K.E = \frac{1}{2}MV^{2}

Where;

K.E represents kinetic energy measured in Joules.

M represents mass measured in kilograms.

V represents velocity measured in metres per seconds square.

Given that mass, m = 2m

Substituting into the equation, we have;

K.E = ½mv²

K.E = ½*2mv²

Cross-multiplying, we have;

2K.E = 2mv²

Hence, if the mass of an object increases by a factor 2, kinetic energy is increased by a factor of 2.

5 0
3 years ago
An ion accelerated through a potential difference of 115 V experiences an increase in kinetic energy of 7.37 x 1017 J. Calculate
riadik2000 [5.3K]

Answer: 6.408(10)^{-19} C

Explanation:

This problem can be solved by the following equation:

\Delta K=q V

Where:

\Delta K=7.37(10)^{-17} J is the change in kinetic energy

V=115 V is the electric potential difference

q is the electric charge

Finding q:

q=\frac{\Delta K}{V}

q=\frac{7.37(10)^{-17} J}{115 V}

Finally:

q=6.408(10)^{-19} C

4 0
3 years ago
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