1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
marysya [2.9K]
1 year ago
13

prove displacement of a body in nth second is given by the S=u+a/2(2n-1) where symbols have their usual meaning

Physics
1 answer:
Maru [420]1 year ago
7 0

The proof that the displacement of a body in nth second which is given by the S=u+a/2(2n-1) is explained below.

<h3>Calculations and Parameters</h3>

Given:

  • u= initial velocity
  • a= acceleration

Displacement during nth second= displacement in n seconds- displacement in (n-1) seconds

= [un + \frac{1}{2} gn^2] - [ u(n-1) + \frac{1}{2} g(n-1)^2]

= (u * 1) + g(n *1) - \frac{g}{2}(1 *1)

Hence, in (n-1) seconds, n has a unit of time and 1 has a unit of time (not a constant)

Therefore, u(m/s) is multiplied by 1  (unit of time)

g(m/s^2) is multiplied by ( n*1 ), having units of time, i.e s^2

g/2 is also multiplied by ( 1 * 1, also having units of time,  i.e s^2

Therefore, the equation is dimensionally correct and we should note that 1 is not a constant in the equation as the time of 1 second in (n-1) second.

Read more about displacement here:

brainly.com/question/2109763

#SPJ1

You might be interested in
An irregular object of mass 3 kg rotates about an axis, about which it has a radius of gyration of 0.2 m, with an angular accele
Citrus2011 [14]

Answer:

The magnitude of the applied torque is 6.0\times10^{-2}\ N-m

(e) is correct option.

Explanation:

Given that,

Mass of object = 3 kg

Radius of gyration = 0.2 m

Angular acceleration = 0.5 rad/s²

We need to calculate the applied torque

Using formula of torque

\tau=I\times\alpha

Here, I = mk²

\tau=mk^2\times\alpha

Put the value into the formula

\tau=3\times(0.2)^2\times0.5

\tau=0.06\ N-m

\tau=6.0\times10^{-2}\ N-m

Hence, The magnitude of the applied torque is 6.0\times10^{-2}\ N-m

7 0
3 years ago
find the distance traveled in km when the average speed is 60 km per hour and the time taken is 3 and 1/2 hours​
Anna35 [415]

Answer:

210 km

Explanation:

60 x 3  1/2 = 210

3 0
3 years ago
What is the electric field strength 7.50 x 10E-1 meters from a 2.8 x 10 E-3 C charged object?
Nadusha1986 [10]

Answer:hi

Explanation:

5 0
3 years ago
Devon has several toy car bodies and motors. The motors have the same mass, but they provide different amounts of force, as show
Grace [21]

Answer:

pretty sure its motor 2, with body 1

Explanation:

4 0
3 years ago
Read 2 more answers
A company records authors reading their books aloud. These recordings are shared with libraries around the world for people to l
9966 [12]

Answer:

c

Explanation:

the loud noise can reduce the quality of the analog signal

5 0
2 years ago
Read 2 more answers
Other questions:
  • A 1.0-kg block of aluminum is at a temperature of 50 Celsius. How much thermal energy will it lose when it’s temperature is redu
    6·1 answer
  • The force that pushes against something traveling through a fluid is called
    14·1 answer
  • True Or False;
    15·1 answer
  • Based on what you learn about jovian moons by watching the videos or reading your textbook, what types of evidence for recent or
    9·1 answer
  • What kind of energy does a skier have standing still at the top of a hill?
    15·1 answer
  • A Carnot heat engine uses a hot reservoir consisting of a large amount of boiling water and a cold reservoir consisting of a lar
    11·1 answer
  • Which carbon reservoirs did not receive any carbon?
    5·1 answer
  • Como estan formados los musculos?
    13·2 answers
  • what is usually caused when dissimilar materials are rubbed together transferring electrons from one to another
    7·1 answer
  • 6 Fig. 6.1 is a full-scale diagram that represents a sound wave travelling in air
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!