The proof that the displacement of a body in nth second which is given by the S=u+a/2(2n-1) is explained below.
<h3>Calculations and Parameters</h3>
Given:
- u= initial velocity
- a= acceleration
Displacement during nth second= displacement in n seconds- displacement in (n-1) seconds
= [![un + \frac{1}{2} gn^2] - [ u(n-1) + \frac{1}{2} g(n-1)^2]](https://tex.z-dn.net/?f=un%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20gn%5E2%5D%20-%20%5B%20u%28n-1%29%20%2B%20%5Cfrac%7B1%7D%7B2%7D%20g%28n-1%29%5E2%5D)
= (u * 1) + g(n *1) -
(1 *1)
Hence, in (n-1) seconds, n has a unit of time and 1 has a unit of time (not a constant)
Therefore, u(m/s) is multiplied by 1 (unit of time)
g(m/s^2) is multiplied by ( n*1 ), having units of time, i.e s^2
g/2 is also multiplied by ( 1 * 1, also having units of time, i.e s^2
Therefore, the equation is dimensionally correct and we should note that 1 is not a constant in the equation as the time of 1 second in (n-1) second.
Read more about displacement here:
brainly.com/question/2109763
#SPJ1