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marysya [2.9K]
1 year ago
13

prove displacement of a body in nth second is given by the S=u+a/2(2n-1) where symbols have their usual meaning

Physics
1 answer:
Maru [420]1 year ago
7 0

The proof that the displacement of a body in nth second which is given by the S=u+a/2(2n-1) is explained below.

<h3>Calculations and Parameters</h3>

Given:

  • u= initial velocity
  • a= acceleration

Displacement during nth second= displacement in n seconds- displacement in (n-1) seconds

= [un + \frac{1}{2} gn^2] - [ u(n-1) + \frac{1}{2} g(n-1)^2]

= (u * 1) + g(n *1) - \frac{g}{2}(1 *1)

Hence, in (n-1) seconds, n has a unit of time and 1 has a unit of time (not a constant)

Therefore, u(m/s) is multiplied by 1  (unit of time)

g(m/s^2) is multiplied by ( n*1 ), having units of time, i.e s^2

g/2 is also multiplied by ( 1 * 1, also having units of time,  i.e s^2

Therefore, the equation is dimensionally correct and we should note that 1 is not a constant in the equation as the time of 1 second in (n-1) second.

Read more about displacement here:

brainly.com/question/2109763

#SPJ1

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We should find \varDelta\overrightarrow{p}=\overrightarrow{p_{f}}-\overrightarrow{p_{i}} (1)with \overrightarrow{p_{i}} the initial momentum and \overrightarrow{p_{f}} the final momentum. Linear momentum is defined as \overrightarrow{p}=m\overrightarrow{v}, using that on (1):

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3 years ago
K-2/5=11k literal equations
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