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marysya [2.9K]
1 year ago
13

prove displacement of a body in nth second is given by the S=u+a/2(2n-1) where symbols have their usual meaning

Physics
1 answer:
Maru [420]1 year ago
7 0

The proof that the displacement of a body in nth second which is given by the S=u+a/2(2n-1) is explained below.

<h3>Calculations and Parameters</h3>

Given:

  • u= initial velocity
  • a= acceleration

Displacement during nth second= displacement in n seconds- displacement in (n-1) seconds

= [un + \frac{1}{2} gn^2] - [ u(n-1) + \frac{1}{2} g(n-1)^2]

= (u * 1) + g(n *1) - \frac{g}{2}(1 *1)

Hence, in (n-1) seconds, n has a unit of time and 1 has a unit of time (not a constant)

Therefore, u(m/s) is multiplied by 1  (unit of time)

g(m/s^2) is multiplied by ( n*1 ), having units of time, i.e s^2

g/2 is also multiplied by ( 1 * 1, also having units of time,  i.e s^2

Therefore, the equation is dimensionally correct and we should note that 1 is not a constant in the equation as the time of 1 second in (n-1) second.

Read more about displacement here:

brainly.com/question/2109763

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[ b) The time of reverberation of an empty hall without and with 500 audiences is 1.5 sec and 1.4 sec respectively. Find the rev
Lilit [14]

The reverberation time with 800 audiences is 0.875 seconds.

<h3>Reverberation time with 800 audience</h3>

R₁V₁ = R₂V₂

where;

  • R₁ is the reverberation time with 400 audience
  • R₂ is the reverberation time with 800 audience
  • V₁ is initial volume
  • V₂ is final volume

R₂ = R₁V₁/V₂

R₂ = (1.4 x 500) / 800

R₂ = 0.875 seconds

Thus, the reverberation time with 800 audiences is 0.875 seconds.

Learn more about reverberation time here: brainly.com/question/9278479

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4 0
2 years ago
A river has a steady speed of 0.500 m/s. a student swims upstream a distance of 1.00 km and swims back to the starting point. (a
Varvara68 [4.7K]
A. Upstream refers to the motion of the swimmer where he is against the current. The resultant speed of the swimmer is equal to the difference of the velocity or speed in still water and that of the river. The time it requires to cover the distance is calculated through the equation,
               t = d / s
where t is time, d is distance, and s is speed. Substituting the known values,
             t = 1000 m / (1.2 m/s - 0.5 m/s) = 1,428.57 seconds

(b) The time it requires for the swimmer to swim in still water,
            t = 1000 m / (1.2 m/s) = 833.33 seconds

(c) Intuitively, it takes longer to cover the distance when there is current because the current will serve as resistance to the motion of the swimmer, partially moving it backwards instead of forward. 


3 0
3 years ago
a 150 kg object takes 1.5 minutes to travel a 2,500 meter straight path. It begins the trip traveling 120 m/s and decelerates to
Firlakuza [10]

Answer:

-1.11 m/s²

Explanation:

v = at + v₀

Given v = 20 m/s, v₀ = 120 m/s, and t = 1.5 min = 90 s:

20 m/s = a (90 s) + 120 m/s

a = -1.11 m/s²

7 0
2 years ago
Read 2 more answers
Question 1 of 20:
xxMikexx [17]

Unlike the IQ, your emotional intelligence (EQ) <u>may be improved over time by becoming more mindful</u>

<u />

Emotional intelligence is the understanding and usage of one's own emotions in a positive way to relieve their stress. It also helps for effective communication, to overcome challenges, to empathize and to defuse any bad situation.

Option A is the correct for IQ ( Intelligence quotient ). Option C is wrong because EQ can be built in any stage of your life. EQ is basically emotions. So option D is incorrect.

Therefore, Unlike the IQ, your emotional intelligence (EQ) may be improved over time by becoming more mindful

<u />

To know more about emotional intelligence

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4 0
1 year ago
Consider the flow of an incompressible Newtonian fluid between two parallel plates that are 4 mm apart. If the upper plate moves
marin [14]

Answer:

Net flow rate = 0.00035 m³/s

Explanation:

The speed of plate 1, U₁ = 5 m/s

The speed of plate 2, U₂ = 1.5 m/s

The two plates are moving in different directions, the net speed will be gotten by taking the difference of the average of the two plates

The average speed due to the movement of plate 1 = U₁/2 = 5/2 = 2.5 m/s

The average speed due to the movement of plate 2 = U₂/2 = 1.5/2

      = 0.75 m/s

The net average speed of the fluid= U₁/2 - U₂/2

The net average speed of the fluid = 2.5 - 0.75 = 1.75 m/s

Net flow rate = Net average speed * Area of the plate

Width of the plate, v = 5 cm = 0.05 m

Distance between the plates = 4 mm = 0.004 m

Area = 0.05 * 0.004

Area = 0.0002 m²

Net flow rate = 1.75 * 0.0002

Net flow rate = 0.00035 m³/s

8 0
3 years ago
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