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Gala2k [10]
3 years ago
11

If the velocity is constant, describe the the slope of the graph on a position vs. time graph.

Physics
2 answers:
zloy xaker [14]3 years ago
7 0
The graph is incresing/decreasing with a constant rate
kvv77 [185]3 years ago
5 0

If the velocity is constant, then the position/time graph has a constant slope, meaning a straight line. 

The slope may be any constant value ... positive, negative, or zero.

             -∞  <  slope  <  +∞


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When scientists first started mapping human genes, they estimated that there were about 2 million genes. By the late 1990s, it w
ICE Princess25 [194]

Answer:

I have the options on e2020. So first, we can definitely mark out D because no way did they stay the same over time. We can cross out B because as scientist "upgrade" over the years, their work will become MORE accurate. Not LESS accurate. So then we are left with A and C. We can cross out C because its doesn't really become accurate and less accurate over time. Then we are left with A which is our answer because scientist can only become more accurate as time goes by with all the new technology advancements they're making.

Hope this helped!! :D (please read whole thing so you understand)

Explanation:

8 0
3 years ago
Read 2 more answers
Two large, parallel, nonconducting sheets of positive charge face each other. What is at points (a) to the left of the sheets, (
alexira [117]

Answer:

a)The electric Field will be zero at the point between the sheets

b)E_1=\dfrac{\sigma}{\epsilon_0}

c)E_2=\dfrac{\sigma}{\epsilon_0}

Explanation:

Let \sigma be the surface charge density of the of the non conducting parallel sheet.Let consider a Gaussian surface in the form of of cylinder such that its cross-sectional is A . Then there will be flux only due to cross sectional area as the curved sectional is perpendicular to the the electric field  so the Electric Flux due to it is zero.

Now using Gauss law we have, E be the electric Field at the distance r from the sheet then

E\times 2A=\dfrac{\sigma A}{\epsilon_0}\\E=\dfrac{\sigma}{2\epsilon_0}

The Field will be away from the sheet and perpendicular to it.

a) The Electric Field between them

E_1=\dfrac{\sigma}{2\epsilon_0}-\dfrac{\sigma}{2\epsilon_0}\\=0

b)The Electric Field to the right of the sheets

E_1=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

c)The Electric Field to the left of the sheets

E_2=\dfrac{\sigma}{2\epsilon_0}+\dfrac{\sigma}{2\epsilon_0}\\=\dfrac{\sigma}{\epsilon_0}

3 0
3 years ago
A 12.0 g bullet was fired horizontally into a 1 kg block of wood. The bullet initially had a speed of 250 m/s. The block of wood
LuckyWell [14K]

Answer:

The rise in height of combined block/bullet from its original position is 0.45m

Explanation:

Given;

mass of bullet, m₁ = 12 g = 0.012 kg

mass of block of wood, m₂ = 1 kg

initial speed of bullet, u₁ = 250 m/s.

initial speed of block of wood, u₂ = 0

From the principle of conservation of linear momentum, calculate the final speed of the combined block/bullet system.

m₁u₁ + m₂u₂ = v(m₁+m₂)

where;

v is the final speed of the combined block/bullet system.

0.012 x 250 + 0 = v (0.012 + 1)

3 = v (1.012)

v = 3/1.012

v = 2.96 m/s

From the principle of conservation of energy, calculate the rise in height of the block/bullet combined from its original position.

¹/₂mv² = mgh

¹/₂v² = gh

¹/₂ (2.96)² = (9.8)h

4.3808 = 9.8h

h = 4.3808/9.8

h = 0.45 m

Therefore, the rise in height of combined block/bullet from its original position is 0.45m

7 0
3 years ago
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Black_prince [1.1K]
<span>
Reaction rates are affected by reactant concentrations and temperature. this is accounted for by the c</span>ollision model.

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3 years ago
What are some of the difficulties with measuring the volume of a gas? Select all that apply.
forsale [732]

Answer:

it is ---D because you can't measure gas and it's mass

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6 0
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