The balanced nuclear equations for the following:(a) β⁻ decay of silicon-32 is (27,14)Si -> (0,-1)beta + (27,15)P
<h3>
What is balanced nuclear equation?</h3>
A nuclear reaction is generally expressed by a nuclear equation, which has the general form, where T is the target nucleus, B is the bombarding particle, R is the residual product nucleus, and E is the ejected particle, and Ai and Zi (where I = 1, 2, 3, 4) are the mass number and atomic number, respectively. Finding a well balanced equation is critical for understanding nuclear reactions. Balanced nuclear equations provide excellent information about the energy released in nuclear reactions. Balancing the nuclear equation requires equating the total atomic number as well as the total mass number before and after the reaction using the rules of atomic number and mass number conservation in a nuclear reaction.
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Answer:
884.56 torr
Explanation:
Formula: 
P = Pressure
V = Volume
T = Temperature in kelvin (Celsius + 273.15)


P = 884.56169
<u>Answer:</u> The temperature at which the food will cook is 219.14°C
<u>Explanation:</u>
To calculate the final temperature of the system, we use the equation given by Gay-Lussac Law. This law states that pressure of the gas is directly proportional to the temperature of the gas at constant pressure.
Mathematically,

where,
are the initial pressure and temperature of the gas.
are the final pressure and temperature of the gas.
We are given:

Putting values in above equation, we get:

Converting the temperature from kelvins to degree Celsius, by using the conversion factor:


Hence, the temperature at which the food will cook is 219.14°C
The answer will be (4) HI because the greater the difference of the bonds in electronegativity, the more polar a bond is.