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andrew11 [14]
4 years ago
15

The city council is discussing whether or not to put fluoride in the city's water supply. Many other towns add it already, but y

our town wants to research the topic before they make a decision. Which would be the best group for them to ask for information on the topic? (1 point) Group of answer choices Citizens from the town who are interested in the topic The company that supplies the fluoride The government agency responsible for monitoring water safety Citizens from another town that currently add fluoride to their water
Physics
1 answer:
earnstyle [38]4 years ago
8 0

Answer:

For anyone who needs this answer in the future the answer is "The government agency responsible for monitoring water safety"

Explanation:

I took the quiz and got it right! It is that answer because the people who's profession is monitoring water safety would be the most reliable to ask this question. Hope this helps.

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Consider the following three concentric systems two thick shells and a solid sphere all conductors The radii in the increasing o
Margarita [4]

Answer:

Explanation:

From the given question, the small sphere was provided with an excess charge of +3 C, while the smaller shell was given an excess of -7 C, it should be -7 C and not 7 C.

So, in light of that, to determine the electric charges values & signs on each of them, we have:

on a = +3 C

on b = -7 C

on c = -7 C

on d = +3 C

on e = -7 C

5 0
3 years ago
Help pls, see picture. Will mark Brainliest
Leno4ka [110]

Answer:

B

Explanation:

the graph shows the line going up (accelerating) and it isn't curving like d so it doesn't stop accelerating

Hope this helps :)

4 0
3 years ago
A parallel beam of light in air makes an angle of 43.5 ∘ with the surface of a glass plate having a refractive index of 1.68. Yo
aniked [119]

Answer:

a) 46.5º  b) 64.4º

Explanation:

To solve this problem we will use the laws of geometric optics

a) For this part we will use the law of reflection that states that the reflected and incident angle are equal

     θ = 43.5º

This angle measured from the surface is

     θ_r = 90 -43.5

     θ_s = 46.5º

b) In this part the law of refraction must be used

     n₁ sin θ₁ = n₂. Sin θ₂

     sin θ₂ = n₁ / n₂ sin θ₁

The index of air refraction is n₁ = 1

The angle is this equation is measured between the vertical line called normal, if the angles are measured with respect to the surface

     θ_s = 90 - θ

     θ_s = 90- 43.5

     θ_s = 46.5º

     sin θ₂ = 1 / 1.68  sin 46.5

     sin θ₂ = 0.4318

     θ₂ = 25.6º

The angle with respect to the surface is

     θ₂_s = 90 - 25.6

     θ₂_s = 64.4º

measured in the fourth quadrant

3 0
3 years ago
A charge of −20 µC is distributed uniformly over the surface of a spherical conductor of radius 11.0 cm. Determine the electric
Alex73 [517]

Answer:

(a) -6.76\times 10^{12}\ N/C

(b) -1.352\times 10^{13}\ N/C

(c) -7.2\times 10^{11}\ N/C

Explanation:

(a)

Given:

Charge on sphere (Q) = -20\ \mu C=-20\times 10^{-6}\ C

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 5 cm = 0.05 m

Coulomb's constant (k) = 9\times 10^{9}\ Nm^2/C^2

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r ≤ R' from the center of sphere is given as:

E=(\frac{kQ}{R^3})r

Plug in the given values and solve for 'E'. This gives,

E_{in}=(\frac{9\times 10^{9}\times -20}{(0.110)^3})\times 0.05\\\\E_{in}=-1.352\times 10^{14}\times 0.05\\\\E_{in}=-6.76\times 10^{12}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)

(b)

Given:

Charge on sphere (Q) = -20\ \mu C=-20\times 10^{-6}\ C

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 10 cm = 0.10 m

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r ≤ R' from the center of sphere is given as:

E=(\frac{kQ}{R^3})r

Plug in the given values and solve for 'E'. This gives,

E_{in}=(\frac{9\times 10^{9}\times -20}{(0.110)^3})\times 0.10\\\\E_{in}=-1.352\times 10^{14}\times 0.10\\\\E_{in}=-1.352\times 10^{13}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)

(c)

Given:

Charge on sphere (Q) = -20\ \mu C=-20\times 10^{-6}\ C

Radius of sphere (R) = 11.0 cm = 0.110 m

Distance from the center (r) = 50 cm = 0.50 m

Now, we know from Gaussian law for uniform charged spheres, the electric field at a distance 'r > R' from the center of sphere is given as:

E=\dfrac{kQ}{r^2}

Plug in the given values and solve for 'E'. This gives,

E_{out}=(\frac{9\times 10^{9}\times -20}{(0.50)^2})\\\\E_{out}=-7.2\times 10^{11}\ N/C(Negative\ sign\ implies\ radially\ inward\ direction)

8 0
4 years ago
What is resistivity?​
Rom4ik [11]

Answer:

Resistivity, electrical resistance of a conductor of unit cross-sectional area and unit length.

Explanation:

A characteristic property of each material, resistivity is useful in comparing various materials on the basis of their ability to conduct electric currents. High resistivity designates poor conductors.

3 0
3 years ago
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