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damaskus [11]
4 years ago
15

Explain in detail the difference between the microstructures of a cold worked sample and Recrystallized sample ?

Engineering
1 answer:
MrRa [10]4 years ago
7 0

Answer:

A recrystallization process differs mainly from a restoration process (microestructures of a cold worked sample) in that  the first, the microstructure of the final product consists mainly of  high angle borders.

Explanation:

The microstructure of a cold worked material has a high energy stored in dislocations and subgrains. During a heat treatment, this microstructure evolves in order to achieve a more stable state by reducing its energy. The complex microscopic mechanisms that take place during this process have been traditionally encompassed in three categories: restoration, recrystallization and grain growth, which will be discussed later.

These processes generally lead to the total or partial recovery of the original properties of the material (ductility, resistance). They can take place under dynamic conditions, that is, during thermomechanical processing or when the material is subsequently deformed at high temperature, and under static conditions, that is, during a heat treatment after thermomechanical processing.

The term <em>restoration</em> encompasses the following succession of micromechanism: formation of dislocation cells,  annihilation of dislocations within them, formation of subgrains and their growth.

<em>A recrystallization process differs mainly from a restoration process in that in the first one the microstructure of the final product is mainly formed by high-angle borders.</em>

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The primary source of voltage for a storage battery is; Active Source

<h3>What is Voltage?</h3>

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Now, there are two primary sources of voltage which are namely active sources and passive sources.

The Active sources delivers power or energy to the circuit while the Passive sources utilizes power or energy from the circuit.

Thus, the storage battery will be an active source

Read more about Voltage at; brainly.com/question/14883923

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1. Which of the following is the ideal way to apply pressure onto pedals?
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I think D. By pressing gradually
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The electric motor exerts a torque of 800 N·m on the steel shaft ABCD when it is rotating at a constant speed. Design specificat
kodGreya [7K]

Answer:

d= 4.079m ≈ 4.1m

Explanation:

calculate the shaft diameter from the torque,    \frac{τ}{r} = \frac{T}{J} = \frac{C . ∅}{l}

Where, τ = Torsional stress induced at the outer surface of the shaft (Maximum Shear stress).

r = Radius of the shaft.

T = Twisting Moment or Torque.

J = Polar moment of inertia.

C = Modulus of rigidity for the shaft material.

l = Length of the shaft.

θ = Angle of twist in radians on a length.  

Maximum Torque, ζ= τ ×  \frac{ π}{16} × d³

τ= 60 MPa

ζ= 800 N·m

800 = 60 ×  \frac{ π}{16} × d³

800= 11.78 ×  d³

d³= 800 ÷ 11.78

d³= 67.9

d= \sqrt[3]{} 67.9

d= 4.079m ≈ 4.1m

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An automobile has a mass of 1200 kg. What is its kinetic energy, in ki, relative to the road when traveling at a velocity of 50
netineya [11]

Answer:

a)Ek=115759.26J

b)23.15kW

Explanation:

kinetic energy(Ek) is understood as that energy that has a body with mass when it travels with a certain speed, it is calculated by the following equation

Ek=0.5mv^{2}

for the first part

m=1200Kg

V=50km/h=13.89m/s

solving for Ek

Ek=0.5(1200)(13.89)^2

Ek=115759.26J

For the second part of the problem we calculate the kinetic energy, using the same formula, then in order to find the energy change we find the difference between the two, finally divide over time (15s) to find the power.

m=1200kg

V=100km/h=27.78m/s

Ek=0.5(1200)(27.78)^2=462963J\\

taking into account all of the above the following equation is inferred

ΔE=\frac{Ek2-EK1}{T}=\frac{462963-115759.26}{15}  =23146.916W=23.15kW

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