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diamong [38]
2 years ago
6

An energy system can be approximated to simply show the interactions with its environment including cold air in and warm air out

, heat transfer inflow and power input. Write a first law balance around the system and solve for the rate of work input to the system.
Engineering
1 answer:
Elenna [48]2 years ago
5 0

Answer: The energy system related to your question is missing attached below is the energy system.

answer:

a) Work done = Net heat transfer

  Q1 - Q2 + Q + W = 0

b)  rate of work input ( W ) = 6.88 kW

Explanation:

Assuming CPair = 1.005 KJ/Kg/K

<u>Write the First law balance around the system and rate of work input to the system</u>

First law balance ( thermodynamics ) :

Work done = Net heat transfer

Q1 - Q2 + Q + W = 0 ---- ( 1 )

rate of work input into the system

W = Q2 - Q1 - Q -------- ( 2 )

where : Q2 = mCp T  = 1.65 * 1.005 * 293 = 485.86 Kw

             Q2 = mCp T = 1.65 * 1.005 * 308 = 510.74 Kw

              Q = 18 Kw

Insert values into equation 2 above

W = 6.88 Kw

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Answer:

<u>1.  B. They work only with numeric digits (based on math)</u>

<u>2. C. French</u>

<u>Explanation:</u>

1.  Computers that are fully digital are those that can process data only expressed in binary code, which is in 0 and 1 (numeric digits).

2. Remember, a byte is the smallest unit of memory in a computer. Eight bits (an octet) make one byte. Furthermore, the naming system for quantities of bytes which is the term "octet" is of French origin.

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What have you learned about designing solutions? How does this apply to engineering? Think of some engineering solutions that st
Andrew [12]

Answer:

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2 years ago
The Danish scientist Niels Bohr proposed a model of the atom that is not totally accurate today but still contains components th
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Answer:

Option B

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7 0
3 years ago
Air pressure is higher above an airfoil.<br> true or false
attashe74 [19]

Answer: true

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6 0
2 years ago
An inductor (L = 400 mH), a capacitor (C = 4.43 µF), and a resistor (R = 500 Ω) are connected in series. A 44.0-Hz AC generator
MakcuM [25]

Answer:

(A) Maximum voltage will be equal to 333.194 volt

(B) Current will be leading by an angle 54.70

Explanation:

We have given maximum current in the circuit i_m=385mA=385\times 10^{-3}A=0.385A

Inductance of the inductor L=400mH=400\times 10^{-3}h=0.4H

Capacitance C=4.43\mu F=4.43\times 10^{-3}F

Frequency is given f = 44 Hz

Resistance R = 500 ohm

Inductive reactance will be x_l=\omega L=2\times 3.14\times 44\times 0.4=110.528ohm

Capacitive reactance will be equal to X_C=\frac{1}{\omega C}=\frac{1}{2\times 3.14\times 44\times 4.43\times 10^{-6}}=816.82ohm

Impedance of the circuit will be Z=\sqrt{R^2+(X_C-X_L)^2}=\sqrt{500^2+(816.92-110.52)^2}=865.44ohm

So maximum voltage will be \Delta V_{max}=0.385\times 865.44=333.194volt

(B) Phase difference will be given as \Phi =tan^{-1}\frac{X_C-X_L}{R}=\frac{816.92-110.52}{500}=54.70

So current will be leading by an angle 54.70

5 0
3 years ago
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