Answer:
The number of complex roots is 6.
Step-by-step explanation:
Descartes's rule of signs tells you that the number of positive real roots is 0. The number of negative real roots will be at most 2. The minimum value of the left side will be between x=0 and x=-1, but will never be negative. Thus all six roots are complex.
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The magnitude of x^3 will exceed the magnitude of x^6 only for values of x between -1 and 1. Since the magnitude of either of these terms will not be more than 1 in that range, the left-side expression must be positive everywhere.
Step-by-step explanation:







option C
a 1 =− 3 1 a, start subscript, 1, end subscript, equals, minus, start fraction, 1, divided by, 3, end fraction a i = a i − 1
MrRa [10]
Answer:

Step-by-step explanation:
Given the sequence


Therefore the sequence is:

This is a geometric sequence where the:
First Term, 
Common ratio, r =-3
We want to determine the sum of the first 75 terms.
For a geometric sequence, the sum:

Therefore:

Answer:
The equation for this circle is 2c(x²+y²) - 8cx + cy = 0
Step-by-step explanation:
We can solve this problem replacing each of the points in the general equation and then solving the system of equations.
The fact that the circle passes by the point (3,-2) means that when x = 3, y = -2. So:


For (1, -2)


For (0,0)


Now we have to find a,b,c, from the following equations
13a+ 3b - 2c = 0
5a + b - 2c = 0
Since we have variables and 2 equations, i am going to write a and b as functions of c.
13a + 3b = 2c
5a + b = 2c
I will write b in the second equation as a function of a and c, and replace in the first equation
b = 2c - 5a
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13a + 3(2c-5a) = 2c
13a + 6cc -15a = 2c
-2a = -4c *(-1)
2a = 4c
a = 2c
-----------
b = 2c - 5a
b = 2c - 5(2c)
b = -8c
The solution for the system is (a,b,c) = (2c, -8c, c). So the equation for this circle is 2c(x²+y²) - 8cx + cy = 0