Answer:
The answer is B. balanced forces
Answer:
1.45 x 10⁻² g CO₂
Explanation:
To find the mass of carbon dioxide, you need to (1) convert grams CH₄ to moles CH₄ (via molar mass), then (2) convert moles CH₄ to moles CO₂ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles CO₂ to grams CO₂ (via molar mass). The final answer should have 3 sig figs to reflect the given value (5.30 x 10⁻³ g).
Molar Mass (CH₄): 12.011 g/mol + 4(1.008 g/mol)
Molar Mass (CH₄): 16.043 g/mol
Combustion of Methane:
1 CH₄ + 2 O₂ ---> 2 H₂O + 1 CO₂
Molar Mass (CO₂): 12.011 g/mol + 2(15.998 g/mol)
Molar Mass (CO₂): 44.007 g/mol
5.30 x 10⁻³ g CH₄ 1 mole 1 mole CO₂ 44.007 g
--------------------------- x ---------------- x --------------------- x ----------------- =
16.043 g 1 mole CH₄ 1 mole
= 0.0145 g CO₂
= 1.45 x 10⁻² g CO₂
Answer:
The statement d) is true: The entropy of the universe is always increased in a spontaneous process.
Explanation:
a), b), c) and e) are false.
a) When no heat exchange occurs between the system and its surroundings
, this process is called an adiabatic process. Because the system does work on the surroundings, w is a negative quantity and there is a decrease in the system’s internal energy (since it cannot exchange heat, it will have to use its internal energy to do work).
b) Breaking a bond will always require energy, whereas forming a bond releases energy. Therefore, if more bonds are broken than formed, the enthalpy of a reaction will be positive.
c) The second law of thermodynamics states that the entropy of the universe increases in a spon
taneous process and remains unchanged in an equilibrium process. Therefore, the entropy of the universe is not always constant.
d) True.
e) According to the Gibbs equation, if ΔH is negative and ΔS is negative, then ΔG will be negative only when TΔS is smaller in magnitude than ΔH. This condition is met when T is small.
Answer:
39,5 grams should be obtained of NaCl
Explanation:
We calculate the weight of 1 mol of NaCl:
Weight 1 mol NaCl= Weight Na + Weight Cl= 23g + 35,5g=58,5 g/mol
4,5M--> 4,5 moles NaCl in 1000ml (1L) of solution
1000ml-----4,5 moles NaCl
150 ml------x=(150 mlx4,5 moles NaCl)/1000ml=0,675 moles NaCl
1 mol NaCl--------------58,5 grams
0,675molesNaCl---x= (0,675molesNaClx58,5 grams)/1 mol NaCl
x= 39,4879 grams
Answer:
3.36 × 10^-19 J
Explanation:
From the formula;
E= hc/wavelength
h= 6.6 ×10^-34 Js
c= 3 × 10^8 ms-1
Wavelength= 589 ×10^-9 m
E= hc/ wavelength
E=6.6 ×10^-34 × 3 × 10^-8/ 589 ×10^-9
E= 3.36 × 10^-19 J