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Black_prince [1.1K]

3 years ago

9

1.When I cook an egg in a microwave oven, the device uses electromagnetic energy to increase the kinetic energy of particles of

matter in the egg.
2.Many stoves and ovens have exhaust fans overhead to remove the rising warm air from the kitchen. The thermal energy is added to air and it rises.

3.When I cook an egg in a pan, thermal energy is transferred as the egg touches the hot surface of the pan. The thermal energy is transferred as objects touch.

choose which one are Conduction, Convection or Radiation

1 answer:

kondaur [170]3 years ago

5 0

Answer:

1: Radiation 2: Convection 3: Conduction

Explanation:

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a proton of mass 1 u travelling with a speed of 3.6 x 10 ^4 m/s has an elastic head on collision with a helium nucleus initially

CaHeK987 [17]

Answer:

Velocity of the helium nuleus = 1.44x10⁴m/s

Velocity of the proton = 2.16x10⁴m/s

Explanation:

From the conservation of linear momentum of the proton collision with the He nucleus:

$P_{1i} + P_{2i} = P_{1f} + P_{2f]$ (1)

<em>where $P_{1i}$ : is the proton linear momentum initial, $P_{2i}$ : is the helium nucleus linear momentum initial, $P_{1f}$ : is the proton linear momentum final, $P_{2f}$ : is the helium nucleus linear momentum final </em>

<u>From (1):</u>

$m_{1}v_{1i} + 0 = m_{1}v_{1f} + m_{2}v_{2f}$ (2)

<em>where m₁ and m₂: are the proton and helium mass, respectively, $v_{1i}$ and $v_{2i}$ : are the proton and helium nucleus velocities, respectively, before the collision, and $v_{1f}$ and $v_{2f}$ : are the proton and helium nucleus velocities, respectively, after the collision </em>

By conservation of energy, we have:

$K_{1i} + K_{2i} = K_{1f} + K_{2f}$ (3)

<em>where $K_{1i}$ and $K_{2i}$ : are the kinetic energy for the proton and helium, respectively, before the colission, and $K_{1f}$ and $K_{2f}$ : are the kinetic energy for the proton and helium, respectively, after the colission </em>

<u>From (3):</u>

$\frac{1}{2}m_{1}v_{1i}^{2} + 0 = \frac{1}{2}m_{1}v_{1f}^{2} + \frac{1}{2}m_{2}v_{2f}^{2}$ (4)

<u>Now we have two equations: (2) ad (4), and two incognits: $v_{1f}$ and $v_{2f}$ . </u>

Solving equation (2) for $v_{1f}$ , we have:

$v_{1f} = v_{1i} -\frac{m_{2}}{m_{1}} v_{2f}$ (5)

<u>From getting (5) into (4) we can obtain the $v_{2f}$ :</u>

$v_{2f}^{2} \cdot (\frac{m_{2}^{2}}{m_{1}} + m_{2}) - 2v_{2f}v_{1i}m_{2} = 0$

$v_{2f}^{2} \cdot (\frac{(4u)^{2}}{1u} + 4u) - v_{2f}\cdot 2 \cdot 3.6 \cdot 10^{4} \cdot 4u = 0$

From solving the quadratic equation, we can calculate the velocity of the helium nucleus after the collision:

$v_{2f} = 1.44 \cdot 10^{4} \frac{m}{s}$ (6)

Now, by introducing (6) into (5) we get the proton velocity after the collision:

$v_{1f} = 3.6 \cdot 10^{4} -\frac{4u}{1u} \cdot 1.44 \cdot 10^{4}$

$v_{1f} = -2.16 \cdot 10^{4} \frac{m}{s}$

The negative sign means that the proton is moving in the opposite direction after the collision.

I hope it helps you!

7 0

4 years ago

Hydrogen sulfide, H2S, and hydrogen chloride, HCl, are both gases at temperatures above –50 °C.

vladimir1956 [14]

Explanation:

A gas at higher temperature is able to gain more heat from the environment/surroundings and has more kinetic energy to diffuse at a faster rate.

Hence a temperature at -20°C is more ideal.

Molar mass of H2S = 34.07g/mol

Molar mass of HCl = 36.45g/mol

Since H2S has a smaller molar mass, the same number of moles of H2S gas will diffuse faster as compared to the same number of moles of HCl gas.

Hence the answer is Hydrogen sulfide at -20°C. (D)

5 0

3 years ago

Write any two difference between air pump and water pump.

Alina [70]

Answer:

See the explanation below.

Explanation:

a)

Pumping water requires equipment with closed housing, so that water is not irrigated from the pumping point.

Fans in some applications do not require closed housings, as air irritation does not create anomalies or areas of nonconformity at the air pumping point.

b)

The pressures in water pumping equipment are usually much higher than those generated with air equipment, since the density of water is much higher than that of air, almost 1000 times higher.

3 0

4 years ago

Comparing Wave A (black) to Wave B (green), Wave A has a

Gennadij [26K]

I think it's C, longer wave length.

7 0

4 years ago

Read 2 more answers

Formula for calculating work done in machines

Archy [21]

Answer:

force×distance

Explanation:

i think that's the answer and it could also be expressed as m×g×d

7 0

3 years ago