Question

A monatomic ideal gas has its volume decreases by a factor of five while its pressure is held constant. Part A What is the change in entropy per atom?

Answer 1

Answer

-5.4098

Explanation:

We know that at constant pressure $volume\proptotemperature$

In question it is given that volume is decreases by $\frac{1}{5}$ times

So $\frac{V_1}{V_2}=\frac{T_1}{T_2}$

$\frac{T_1}{T_2}=\frac{V_1}{\frac{V_1}{5}}$

$T_2=\frac{T_1}{5}$

The change in entropy is given by

$\Delta s=\frac{3}{2}Nln\frac{T_2}{T_1}+Nln\frac{\frac{v_1}{5}}{v_1}$

$\frac{\Delta s}{N}=\frac{3}{2}ln\frac{1}{5}+ln\frac{1}{5}$

$\frac{\Delta s}{N}=-5.4098$