Ask question

Ask question

All categories

3 years ago

10

A monatomic ideal gas has its volume decreases by a factor of five while its pressure is held constant. Part A What is the chang

e in entropy per atom?

1 answer:

Levart [38]3 years ago

5 0

Answer

-5.4098

Explanation:

We know that at constant pressure $volume\proptotemperature$

In question it is given that volume is decreases by $\frac{1}{5}$ times

So $\frac{V_1}{V_2}=\frac{T_1}{T_2}$

$\frac{T_1}{T_2}=\frac{V_1}{\frac{V_1}{5}}$

$T_2=\frac{T_1}{5}$

The change in entropy is given by

$\Delta s=\frac{3}{2}Nln\frac{T_2}{T_1}+Nln\frac{\frac{v_1}{5}}{v_1}$

$\frac{\Delta s}{N}=\frac{3}{2}ln\frac{1}{5}+ln\frac{1}{5}$

$\frac{\Delta s}{N}=-5.4098$

You might be interested in

What is an invasive species plant??

lianna [129]

Japanese Honeysuckle

6 0

3 years ago

Arrange the following decisions accordingly. Be guided by the chronological circumstances happened from the start of the game. U

Snezhnost [94]

Answer: Use Roman Numerals in answering. 11. - 27310189. ... Hiwalay! Hatol. Unang puntos, Bughaw! 12. Hinto! Pula, pangalawang laglag. Panalo ...

Explanation:. Hinto! Hiwalay! Bughaw, 1 puntos. Unang paglabag! 14. Hinto! Bughaw, pangalawang paglabag

3 0

1 year ago

Mars has two moons, Phobos and Deimos. Phobos orbits Mars at a distance of 9380 km from Mars's center, while Deimos orbits at 23

Sloan [31]

Answer:

The ratio is $\frac{T_1}{T_2} = 3.965$

Explanation:

From the question we are told that

The radius of Phobos orbit is R_2 = 9380 km

The radius of Deimos orbit is $R_1 = 23500 \ km$

Generally from Kepler's third law

$T^2 = \frac{ 4 * \pi^2 * R^3}{G * M }$

Here M is the mass of Mars which is constant

G is the gravitational constant

So we see that $\frac{ 4 * \pi^2 }{G * M } = constant$

$T^2 = R^3 * constant$

=> $[\frac{T_1}{T_2} ]^2 = [\frac{R_1}{R_2} ]^3$

Here $T_1$ is the period of Deimos

and $T_1$ is the period of Phobos

So

$[\frac{T_1}{T_2} ] = [\frac{R_1}{R_2} ]^{\frac{3}{2}}$

=> $\frac{T_1}{T_2} = [\frac{23500 }{9380} ]^{\frac{3}{2}}]$

=> $\frac{T_1}{T_2} = 3.965$

8 0

3 years ago

How much work is done if I use 5N of force to move an object 2 meters

sweet-ann [11.9K]

It’s 10 joules. W=FD, W=5•2=10

8 0

3 years ago

Church organs have a set of pipes with different lengths. With those different pipes organs can produce sounds over a wide range

Paraphin [41]

Answer: The shortest possible wavelength of sound the organ can produce is 0.224 m

Explanation:

To calculate the wavelength of light, we use the equation:

$\lambda=\frac{c}{\nu}$

where,

$\lambda$ = wavelength of the light

c = speed of light = $331m/s$

As wavelength and frequency follows inverse relation, shortest wavelength is produced by highest frequency.

$\nu$ = highest frequency of light = $1.48kHz=1.48\times 10^3Hz=1.48\times 10^3s^{-1}$ $1Hz=1s^{-1}$

$\lambda=\frac{331m/s}{1.48\times 10^3s^{-1}}=0.224m$

Thus the shortest possible wavelength of sound the organ can produce is 0.224 m

8 0

3 years ago