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noname [10]
3 years ago
10

A monatomic ideal gas has its volume decreases by a factor of five while its pressure is held constant. Part A What is the chang

e in entropy per atom?
Physics
1 answer:
Levart [38]3 years ago
5 0

Answer

-5.4098

Explanation:

We know that at constant pressure volume\proptotemperature

In question it is given that volume is decreases by \frac{1}{5} times

So \frac{V_1}{V_2}=\frac{T_1}{T_2}

\frac{T_1}{T_2}=\frac{V_1}{\frac{V_1}{5}}

T_2=\frac{T_1}{5}

The change in entropy is given by

\Delta s=\frac{3}{2}Nln\frac{T_2}{T_1}+Nln\frac{\frac{v_1}{5}}{v_1}

\frac{\Delta s}{N}=\frac{3}{2}ln\frac{1}{5}+ln\frac{1}{5}

\frac{\Delta s}{N}=-5.4098

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On a frictionless horizontal air table, puck A (with mass 0.254 kg ) is moving toward puck B (with mass 0.367 kg ), which is ini
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Answer:

v_a=0.8176 m/s

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

Explanation:

According to the law of conservation of linear momentum, the total momentum of both pucks won't be changed regardless of their interaction if no external forces are acting on the system.

Being m_a and m_b the masses of pucks a and b respectively, the initial momentum of the system is

M_1=m_av_a+m_bv_b

Since b is initially at rest

M_1=m_av_a

After the collision and being v'_a and v'_b the respective velocities, the total momentum is

M_2=m_av'_a+m_bv'_b

Both momentums are equal, thus

m_av_a=m_av'_a+m_bv'_b

Solving for v_a

v_a=\frac{m_av'_a+m_bv'_b}{m_a}

v_a=\frac{0.254Kg\times (-0.123 m/s)+0.367Kg (0.651m/s)}{0.254Kg}

v_a=0.8176 m/s

The initial kinetic energy can be found as (provided puck b is at rest)

K_1=\frac{1}{2}m_av_a^2

K_1=\frac{1}{2}(0.254Kg) (0.8176m/s)^2=0.0849 J

The final kinetic energy is

K_2=\frac{1}{2}m_av_a'^2+\frac{1}{2}m_bv_b'^2

K_2=\frac{1}{2}0.254Kg (-0.123m/s)^2+\frac{1}{2}0.367Kg (0.651m/s)^2=0.07969 J

The change of kinetic energy is

\Delta K=0.07969 J - 0.0849 J = -0.00521 J

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Momentum for a system can be conserved in one direction while not being conserved in another. What is the anglebetween the direc
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Answer:

90°

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