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vladimir2022 [97]
3 years ago
13

What happens if you move a magnet near a coil of wire? A. Current is induced. B. Power is consumed. C. The coil becomes magnetiz

ed. D. The magnet's field is reduce
Physics
2 answers:
Sergio [31]3 years ago
5 0
There is a voltage that appears between the ends of the wire. If the ends of the wire are connected, or there is a conductor between the both of them, then a current will flow in the wires. Hope it helps
Alexeev081 [22]3 years ago
5 0

Answer:

If you move a magnet near a coil of wire then the current is induced.

Option A is correct.

Explanation:

According to Faraday's law of induction

If we move a magnet near a coil of wire then an emf (electromotive force) is induced in the wire which produces current in it. The induced emf is linked to the rate of change of the magnetic flux linked with the coil.

The induced emf is given by:

\epsilon =- \dfrac{N d\phi}{dt}

Where, \phi = magnetic flux

\epsilon = -\dfrac{N d(BA)}{dt}

Where, B = magnetic field

A = area of coil

N = number of turns

Hence,  If you move a magnet near a coil of wire then the current is induced.

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prohojiy [21]
From the information given above, 
Mass [M] = 28 g
Change in temperature = 29 - 7 = 22 
Specific heat of iron = 0.449 [This value is constant]
The formula for calculating heat absorbed, Q is
Q = Mass * Specific heat of Iron * change in temperature
Q = 28 * 0.449 * 22 = 276.58 J<span />
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3 years ago
What is it called when a surface takes light in without reflecting it
andrew-mc [135]
Reflection from such a rough surface is called diffuse reflection and appears matte
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4 years ago
Read 2 more answers
A body which has surface area 5cm² and temperature of 727°C radiates 300J of energy in one minute. Calculate it's emissivity giv
cestrela7 [59]
<h2>Answer: 0.17</h2>

Explanation:

The Stefan-Boltzmann law establishes that a black body (an ideal body that absorbs or emits all the radiation that incides on it) "emits thermal radiation with a total hemispheric emissive power proportional to the fourth power of its temperature":  

P=\sigma A T^{4} (1)  

Where:  

P=300J/min=5J/s=5W is the energy radiated by a blackbody radiator per second, per unit area (in Watts). Knowing 1W=\frac{1Joule}{second}=1\frac{J}{s}

\sigma=5.6703(10)^{-8}\frac{W}{m^{2} K^{4}} is the Stefan-Boltzmann's constant.  

A=5cm^{2}=0.0005m^{2} is the Surface area of the body  

T=727\°C=1000.15K is the effective temperature of the body (its surface absolute temperature) in Kelvin.

However, there is no ideal black body (ideal radiator) although the radiation of stars like our Sun is quite close.  So, in the case of this body, we will use the Stefan-Boltzmann law for real radiator bodies:

P=\sigma A \epsilon T^{4} (2)  

Where \epsilon is the body's emissivity

(the value we want to find)

Isolating \epsilon from (2):

\epsilon=\frac{P}{\sigma A T^{4}} (3)  

Solving:

\epsilon=\frac{5W}{(5.6703(10)^{-8}\frac{W}{m^{2} K^{4}})(0.0005m^{2})(1000.15K)^{4}} (4)  

Finally:

\epsilon=0.17 (5)  This is the body's emissivity

3 0
3 years ago
How much work does it take to move a 50 μC charge<br> against a 12 V potential difference?
lukranit [14]
<span>work =V*Q =12*50*10^-6

The total work done will be equal to 

work = V.Q

which means 

w= 12 . 50.10^-6
Hence,
w= 0.0006 J</span>
8 0
3 years ago
How much time is needed to produce 720 Joules of work if 90 watts of power is used?
Tems11 [23]

Answer:

8 seconds

Explanation:

power (P) is defined as the rate at which work is done.

power is measured in Watts (W) , when the work done is measured in Joules (J) and time in seconds

by the definition of power,

Power=\frac{work.done}{time.taken} \\ \\ time.taken=\frac{work.done}{power}\\=\frac{720J }{90W} \\ \\ =8 s

3 0
3 years ago
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