The volume of the shell that you described would be:
Now we can rewrite the given integral:
I have attached the picture explaining how we got the formula for the volume.
On the picture, I marked the rectangle. You can of this rectangle as the base, and the height would be the circumference of the cylinder.
from rest
dist = 1/2 accn timextime
=1/2 3.2 32.8x32.8
about 1.6x900 m/s ... 1350m
Answer:
Larger tubines generate more electricity.
Explanation:
Larger blades allow the turbine to capture more of the kinetic energy of the wind by moving more air through the rotors. However, larger blades require more space and higher wind speeds to operate. This distance is necessary to avoid interference between turbines, which decreases the power output.
Answer:
The wavelengths of C1 is 10.4m, A6 is 0.193m and B7 is 0.0861m
Explanation:
Using the formula V = f×λ . Then substitute the following values into the formula:
a) v=340m/s
f=32.7 Hz
λ=V ÷ f
= 340 ÷ 32.7
= 10.4m (3s.f)
b) λ=340 ÷ 1760
= 0.193m (3s.f)
c) λ=340÷3951.1
= 0.0861m (3s.f)
(Correct me if I am wrong)
Answer:
The index of refraction of the liquid is 1.35.
Explanation:
It is given that,
Critical angle for a certain air-liquid surface, 
Let n₁ is the refractive index of liquid and n₂ is the refractive index of air, n₂ =1
Using Snell's law for air liquid interface as :
So, the index of refraction of the liquid is 1.35. Hence, this is the required solution.
