Answer:
compacting
Explanation:
i don't think there is very much explanation, the snow falls and compacts the ice to become giant lol
A ) decrease.
B ) increase.
C ) increase, then decrease.
D ) not change.
The answer is A) decrease
Take pushing a box, for example-- You push your hardest then give out, still trying to push the box. You are doing less work than what you have started with!
( Mind marking me for branliest? ; ) )
If a student took seven science classes, his/her at score would be 1200.
<h3>What is a graph?</h3>
A graph is a relationship in which data is presented on the axes of cartesian coordinates. The presentation of the graph must be such that it is easy to read off the graph.
Now we can see that the graph is a plot of SAT scores versus the number of science classes that students take. In this case, the slope would tell us the score per subject of a student in the SAT.
a) The mathematical model that re[resents this graph is;
y =100x + 500
b) The slope of the graph must be obtained by the use of two points thus;
m = y2 - y1/x2 - x1
m = 600 - 500/1 - 0
m = 100
c) Using the relation;
y = mx + c
m = 100
c = 500
y = 100(7) + 500
y = 1200
Thus if a student took seven science classes, his/her at score would be 1200.
Learn more about graph:brainly.com/question/16608196
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Net force = (mass) x (acceleration)... that’s Newton’s 2nd law of motion.
Net force = (15kg) x (10 m/s squared)
Net force = 150 Newtons.
Answer: 909 m/s
Explanation:
Given
Mass of the bullet, m1 = 0.05 kg
Mass of the wooden block, m2 = 5 kg
Final velocities of the block and bullet, v = 9 m/s
Initial velocity of the bullet v1 = ? m/s
From the question, we would notice that there is just an object (i.e the bullet) moving before the collision. Also, even after the collision between the bullet and wood, the bullet and the wood would move as one object. Thus, we would use the conservation of momentum to solve
m1v1 = (m1 + m2) v, on substituting, we have
0.05 * v1 = (0.05 + 5) * 9
0.05 * v1 = 5.05 * 9
0.05 * v1 = 45.45
v1 = 45.45 / 0.05
v1 = 909 m/s
Thus, the original velocity of the bullet was 909 m/s
