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Svet_ta [14]
3 years ago
10

An oscillating block-spring system has a mechanical energyof 1.00 J and amplitude of 10.0 cm and a maximum speed of 1.20m/s. Fin

d (a) the spring constant and (b) the mass of theblock, and (c) the frequency of oscillation.
Physics
1 answer:
Debora [2.8K]3 years ago
6 0

Answer:

Explanation:

Given

Mechanical Energy of Spring-Block system is 1 J

Maximum Amplitude is A=10 cm

maximum speed v_{max}=1.2 m/s

Suppose x=A\sin \omega tbe general equation of motion of spring-mass system

where A=max amplitude

\omega=Natural frequency of oscillation

t=time

v_{max}=A\omega =1.2

0.1\cdot \omega =1.2

\omega =12 rad/s

maximum kinetic Energy must be equal to total Mechanical Energy when spring is un deformed i.e. at starting Position

\frac{1}{2}mv_{max}^2=1

m=\frac{2}{1.2^2}=\frac{2}{1.44}=1.38 kg

Also \omegais also given by

\omega =\sqrt{\frac{k}{m}}

k=\omega ^2\cdot m

where k= spring constant

k=12^2\cdot 1.38

k=200 N/m

             

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