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Svet_ta [14]
4 years ago
10

An oscillating block-spring system has a mechanical energyof 1.00 J and amplitude of 10.0 cm and a maximum speed of 1.20m/s. Fin

d (a) the spring constant and (b) the mass of theblock, and (c) the frequency of oscillation.
Physics
1 answer:
Debora [2.8K]4 years ago
6 0

Answer:

Explanation:

Given

Mechanical Energy of Spring-Block system is 1 J

Maximum Amplitude is A=10 cm

maximum speed v_{max}=1.2 m/s

Suppose x=A\sin \omega tbe general equation of motion of spring-mass system

where A=max amplitude

\omega=Natural frequency of oscillation

t=time

v_{max}=A\omega =1.2

0.1\cdot \omega =1.2

\omega =12 rad/s

maximum kinetic Energy must be equal to total Mechanical Energy when spring is un deformed i.e. at starting Position

\frac{1}{2}mv_{max}^2=1

m=\frac{2}{1.2^2}=\frac{2}{1.44}=1.38 kg

Also \omegais also given by

\omega =\sqrt{\frac{k}{m}}

k=\omega ^2\cdot m

where k= spring constant

k=12^2\cdot 1.38

k=200 N/m

             

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Paha777 [63]

Answer: The correct answer is option (A).

Explanation:

Momentum of the car with 0.04 kg mass , which travelling with velocity of 2.00 m/s

P_1=mass\times velocity=m_1\times v_1=0.04 kg\times 2.00 m/s=8.00 kg m/s

Then the maximum speed of the another car in order to not to break the eggs will be same as first car:

P_1=P_2

0.08 kg m/s=m_2\times v_2=0.08 kg\times v_2

v_2=1 m/s

Speed slightly more than 1 m/s will increase the momentum of second car and the eggs will break. So, from the given options the minimum speed need by the second car will be 1.42m/s.

4 0
4 years ago
Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B , with a mass of 8.0 kg, is moving in the opposi
Anon25 [30]
Consider velocity to the right as positive.

First mass:
m₁ = 4.0 kg
v₁ = 2.0 m/s to the right

Second mass:
m₂ = 8.0 kg
v₂ = -3.0 m/s to the left

Total momentum of the system is
P = m₁v₁ + m₂v₂
   = 4*2 + 8*(-3)
  = -16 (kg-m)/s

Let v (m/s) be the velocity of the center of mass of the 2-block system.

Because momentum of the system is preserved, therefore
(m₁+m₂)v= -16
(4+8 kg)*(v m/s) = -16 (kg-m)/s
v = -1.333 m/s

Answer:
The center of mass is moving at 1.33 m/s to the left.
5 0
4 years ago
Why is it not advisable to touch a canvas tent from inside when it is raining?​
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Name three categories that are used to classify the elements in the periodic table?
nikitadnepr [17]

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6 0
3 years ago
Read 2 more answers
Suppose a two-level system is in a bath with temperature 247 K. The energy difference between the two states is 1.1 × 10-21 J. W
Alik [6]

Answer:

The probability of higher energy state is 0.4200.

Explanation:

Given that,

Temperature = 247 K

Energy difference between two states E_{2}-E_{1}=1.1\times10^{-21}\ J

We need to calculate the probability of higher energy state

Probability of E_{1}= e^{-\beta E_{1}}

Probability of E_{2}= e^{-\beta E_{2}}

The total probability is

e^{-\beta E_{1}}+e^{-\beta E_{1}}=1

Here, E₁ = lower energy state

E₂ = higher energy state

Put the value of E₁ in to the formula

e^{-\beta(E_{2}-1.1\times10^{-21})}+e^{-\beta E_{1}}=1

e^{-\beta E_{2}}(e^{\beta 1.1\times10^{-21}}+1)=1

e^{\beta E_{2}}=\dfrac{1}{1+e^{\dfrac{1.1\times10^{-21}}{KT}}}

Here, \beta=\dfrac{1}{KT}

Put the value into the formula

e^{\beta E_{2}}=\dfrac{1}{1+e^{\dfrac{1.1\times10^{-21}}{1.380\times10^{-23}\times247}}}

e^{\beta E_{2}}=0.4200

Hence, The probability of higher energy state is 0.4200.

4 0
3 years ago
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