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ch4aika [34]
3 years ago
8

Easy points!

Chemistry
1 answer:
podryga [215]3 years ago
3 0
The soda an air is most likely bubbling up and is going to explode.
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Propane gas (C3H8) burns completely in the presence of oxygen gas (O2) to yield carbon dioxide gas (CO2) and water vapor (H2O).
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Oxen beacon is great for your self halllway
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An atom that has 13 protons and 15 neutrons is isotope of the element A.) nickel B.) silicon C.) aluminum D.) phosphorus. Why?
joja [24]

An atom that has 13  protons and 15  neutrons  is isotope  of Aluminium (answer C)

<u><em>Explanation</em></u>

  • Isotope  is a form of the same element with   the equal number of protons but difference number  of neutrons  in  their nuclei.
  • In other words isotope has the same  atomic number but different mass  number.
  • Atomic  number of a element is determined by number of  protons of an element.

  • from the  periodic table   Aluminum in atomic number 13 therefore  it has 13 protons  <em>therefore an atom that  has 13  protons and 15 neutrons is   a isotope  of Aluminium. </em>
6 0
3 years ago
Read 2 more answers
What are the 3 principles of the Kinetic molecular theory?
Sever21 [200]

Answer:

u already know the answer

Explanation:answer

6 0
3 years ago
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(14.1.50) 0.03 mol of helium are enclosed in a cylinder with a piston which maintains a constant pressure in the helium. Initial
icang [17]

Answer:

a) 0.210 j /k

b) 0.032 j/k

Explanation:

Find the attachment for solution

3 0
3 years ago
A 100.0 mL solution containing 0.864 g of maleic acid (MW=116.072 g/mol) is titrated with 0.276 M KOH. Calculate the pH of the s
Lilit [14]

Answer:

pH = 1.32

Explanation:

                 H₂M + KOH ------------------------ HM⁻ + H₂O + K⁺

This problem involves a weak diprotic acid which we can solve by realizing they amount  to buffer solutions.  In the first  deprotonation if all the acid is not consumed we will have an equilibrium of a wak acid and its weak conjugate base. Lets see:

So first calculate the moles reacted and produced:

n H₂M = 0.864 g/mol x 1 mol/ 116.072 g  =  0.074 mol H₂M

54 mL x  1L / 1000 mL x 0. 0.276 moles/L = 0.015 mol KOH

it is clear that the maleic acid will not be completely consumed, hence treat it as an equilibrium problem of a buffer solution.

moles H₂M left = 0.074 - 0.015 = 0.059

moles HM⁻ produced = 0.015

Using the Henderson - Hasselbach equation to solve for pH:

ph = pKₐ + log ( HM⁻/ HA) = 1.92 + log ( 0.015 / 0.059) = 1.325

Notes: In the HH equation we used the moles of the species since the volume is the same and they will cancel out in the quotient.

For polyprotic acids the second or third deprotonation contribution to the pH when there is still unreacted acid ( Maleic in this case) unreacted.

           

3 0
3 years ago
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