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3 years ago

7

How is a fireplace an example of both convection and radiation?

1 answer:

slega [8]3 years ago

5 0

A fire spreads by transferring heat in 3 ways, Raditation, convection, and Conduction :)

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Object A experiences an attractive force of 50 N when it comes close to Object B. If Object A is positively charged, what can yo

denis23 [38]

It is B since they are traveling at the same speed one is positive so the other had to be negative hope this helps;)))))

4 0

3 years ago

Read 2 more answers

What happens to the rock structure during each of type of change?

EastWind [94]

Previous rocks melt and collide and to form igneous rocks.
Igneous rocks disintegrate due to weather disruptions and get carried away by water, where they form sedimentary rock strata by lithification.
Igneous and sedimentary change by heat and pressure to form metamorphic rocks.
Metamorphic rocks melt and become igneous rocks.

3 0

3 years ago

2) A motorcycle is moving at a constant speed of 40 km/h. How long does it take the motorcycle to

docker41 [41]

Answer:

2 hours

Explanation:

The motorcycle travels 40 km per hour.

80km / 40km/h = 2 hours.

7 0

4 years ago

Read 2 more answers

Which statement is true if the refractive index of medium A is greater than that of medium B?

allsm [11]

Answer:

I think it is C

Explanation:

7 0

3 years ago

An electron with velocity v = 1.0 ´ 106 m/s is sent between the plates of a capacitor where the electric field is E = 500 V/m. I

oksano4ka [1.4K]

Answer:

The deviation in path is $4.39 \times 10^{-3}$

Explanation:

Given:

Velocity $v = 1 \times 10^{6}$ $\frac{m}{s}$

Electric field $E = 500$ $\frac{V}{m}$

Distance $x = 1 \times 10^{-2}$ m

Mass of electron $m = 9.1 \times 10^{-31}$ kg

Charge of electron $q = 1.6 \times 10^{-19}$ C

Time taken to travel distance,

$t = \frac{x}{v}$

$t = \frac{1 \times 10^{-2} }{1 \times 10^{6} }$

$t = 10^{-8}$ sec

Acceleration is given by,

$F = qE$

$ma = qE$

$a = \frac{qE}{m}$

$a = \frac{1.6 \times 10^{-19} \times 500}{9.1 \times 10^{-31} }$

$a = 8.77 \times 10^{13}$ $\frac{m}{s^{2} }$

For finding the distance, we use kinematics equations.

$y = vt + \frac{1}{2} at^{2}$

Where $v = 0$ because here initial velocity zero

$y = \frac{1}{2} at^{2}$

$y = \frac{1}{2} \times 8.77 \times 10^{13 } \times (10^{-2} )^{2}$

$y = 4.39 \times 10^{-3}$ m

Therefore, the deviation in path is $4.39 \times 10^{-3}$

6 0

3 years ago