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PtichkaEL [24]
3 years ago
7

How is a fireplace an example of both convection and radiation?

Physics
1 answer:
slega [8]3 years ago
5 0
A fire spreads by transferring heat in 3 ways, Raditation, convection, and Conduction :)
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Given the recent evidence suggesting that species change due to a certain genetic variations, what would be true?
boyakko [2]

Answer:

c) mutation and natural selection both cause changes in a population

Explanation:

Hope it help

Mark me as brainliest

6 0
3 years ago
A horizontal net force F is exerted on an object at rest. The object starts at x=0 m and has a speed of 4.0 m/s after moving 4.0
Alex_Xolod [135]

Explanation:

The solution is be found in the attachment.

8 0
3 years ago
A 1560-kilogram truck moving with a speed of 28.0 m/s runs into the rear end of a 1070-kilogram stationary car. If the collision
Nimfa-mama [501]

Answer:

Δ KE =  249158.6 kJ  

Explanation:

given data

Truck mass  M =  1560 Kg

Truck initial speed, u = 28 m/s

mass of car m = 1070 Kg

initial speed of car u1 = 0 m/s

solution

first we get here final speed by using conservation of momentum  that is express as

Mu = (M+m) V     .......................1

put here  value we get

1560 × 28 = (1560 + 1070 ) V

solve it we get

final speed V = 16.60 m/s

and

Change in kinetic energy  will be here

Δ KE =   \frac{1}{2} Mu^2 - \frac{1}{2}(M+m)V^2         .................2

put here value and we get

 Δ KE = \frac{1}{2}\times 1560\times 28^2 - \frac{1}{2}\times (1560 + 1070)\times 16.60^2  

solve it we get

Δ KE =  249158.6 kJ  

6 0
3 years ago
Which of the following would have the greatest force of gravitational attraction?
zysi [14]
Which of the following is it though...?
4 0
3 years ago
Two parallel copper rods supply power to a high-energy experiment, carrying the same current in opposite directions. The rods ar
mart [117]

Answer:

the maximum allowable current is 7302.967  amperl

Explanation:

The computation of the maximum allowable current is shown below;

Force F = mean ÷ 4π 2 I_1 I_2 ÷d  × ΔL

200 N = (10)^-7 (2I × I) ÷ 0.08 × 1.5

200 = 3.75 × 10^-6 I^2

I = √200 ÷ √ 3.75 × 10^-6

= 7302.967  amperl

Hence, the maximum allowable current is 7302.967  amperl

Basically we applied the above formula

6 0
3 years ago
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