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2 years ago

6

The game was played by swinging the big mallet down hard enough to cause the bell to ring. If it took a 44 newton force to ring

the bell, and George got it to go only 75% of the way up, how many newtons of force did George exert with the mallet on the bell?
A.
44 newtons
B.
66 newtons
C.
33 newtons
D.
11 newtons

1 answer:

nata0808 [166]2 years ago

3 0

I think C. 33 newtons

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A 0.125 kg hockey puck moving at 20.0 m/s is caught and held by an 85.0 kg goalkeeper at rest. After catching the puck, with wha

jenyasd209 [6]

Answer:

a

Explanation:cuz i saiad so

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3 years ago

How many electrons does it take to make up 4.33 C of charge?

Dovator [93]

Answer:

Number of electrons, $n=2.7\times 10^{19}$

Explanation:

It is given that,

Charge, q = 4.33 C

We need to find the number of electrons that make 4.33 C of charge. According to quantization of charge as :

$q=ne$

n = number of electrons

e = electron's charge

$n=\dfrac{q}{e}$

$n=\dfrac{4.33\ C}{1.6\times 10^{-19}\ C}$

$n=2.7\times 10^{19}$

So, the number of electrons are $2.7\times 10^{19}$ Hence, this is the required solution.

7 0

2 years ago

A circuit containing an inductor and a capacitor in series is designed to have a resonant frequency of 4511 Hz. If the inductor

OLEGan [10]

Answer:

(e) $6.835\times 10^{-7}F$

Explanation:

At resonance we know that $X_l=X_C$

That is $\omega L=\frac{1}{\omega C}$

$\omega ^2=\frac{1}{LC}$

$\omega =\frac{1}{\sqrt{LC}}$

$f=\frac{1}{2\pi \sqrt{LC}}$

We have given resonance frequency f =4511 Hz and inductance L=1.82 mH

So $4511=\frac{1}{2\pi \sqrt{LC}}$

$LC=\frac{1}{4\pi ^2\times 4511^2}$

$LC=1.244\times 10^{-9}$

$C=\frac{1.244\times 10^{-9}}{1.82\times 10^{-3}}=0.6835\times 10^{-6}=6.835\times 10^{-7}F$

So option e is the correct answer

3 0

2 years ago

When the driver presses the brake pedal, his car stops with an acceleration of - 8.7 m/s. How far will the car travel while comi

klemol [59]

Answer:

D. 5.7 m

Explanation:

The acceleration of the car is -8.7 m/s² and the car has an initial speed (u) of 10 m/s. The car said to come to rest, that means that the final velocity (v) of the car is 0 m/s.

To find the distance traveled by the car (s) before complete stop, this equation is being used:

v² = u² + 2as

$2as=v^2-u^2\\s=\frac{v^2-u^2}{2a}\\ Substituting:\\s=\frac{0-10^2}{2*-8.7}\\ s=\frac{-100}{17.4}\\ s=5.7\ m$

The car traveled 5.7 m before coming to a complete stop

3 0

3 years ago

The 2779-m Brooklyn-Battery Tunnel, connecting Brooklyn and Manhattan, is one of the world's longest underwater vehicular tunnel

Marina CMI [18]

For a cylinder that has both ends open resonant frequency is given by the following formula:
$f= \frac{nv}{2L}$
Where n is the resonance node, v is the speed of sound in air and L is the length of a cylinder.
The fundamental frequency is simply the lowest resonant frequency.
We find it by plugging in n=1:
$f_0= \frac{v}{2L}=\frac{343}{2\cdot 2779}=0.062 Hz$
To find what harmonic has to be excited so that it resonates at f>20Hz we simply plug in f=20 Hz and find our n:
$20= \frac{n343}{2\cdot 2779} =n\cdot f_0$
We can see that any resonant frequency is simply a multiple of a base frequency.
Let us find which harmonic resonates with the frequency 20 Hz:
$20=n\cdot f_0\\ n=\frac{20}{0.062}=322.58$
Since n has to be an integer, final answer would be 323.

3 0

3 years ago