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AysviL [449]
2 years ago
6

The game was played by swinging the big mallet down hard enough to cause the bell to ring. If it took a 44 newton force to ring

the bell, and George got it to go only 75% of the way up, how many newtons of force did George exert with the mallet on the bell?
A.
44 newtons
B.
66 newtons
C.
33 newtons
D.
11 newtons
Physics
1 answer:
nata0808 [166]2 years ago
3 0
I think C. 33 newtons
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3 years ago
An electron is moving in the presence of an electric field of 400 N/C. What force does the electron experience?
yanalaym [24]

Answer:

Explanation:

Given

Electric Field strength E=400\ N/C

charge of electron q=1.6\times 10^{-19}\ C

Force on the charge particle is given by

F=qE

F=1.6\times 10^{-19}\times 400

F=640\times 10^{-19}\ N

but this force will be acting in the direction opposite to the direction of Electric field because electron is negatively charged                                            

8 0
3 years ago
A stone is thrown vertically upward at a speed of 41.50 m/s at time t=0. A second stone is thrown upward with the same speed 3.0
lubasha [3.4K]

Answer:

t1 = t2 + 3.02         V = 41.5

V t1 - 1/2 g t1^2 = V t2 - 1/2 g t2^2

Both stones reach the same height after the specified times

V (t1 - t2) = g/2 (t1^2 - t2^2) = g/2 (t1 - t2) (t1 + t2)

2 V / g = t1 + t2 = 2t1 + 3.02

t1 = V / g - 1.51 = 41.5 / 9.8 -1.51 = 2.72 s

t2 = t1 + 3.02 = 5.74 sec

Check:

41.5 * 2.72 - 4.9 * 2.72^2 = 76.6 m

41.5 * 5.74 - 4.9 * 5.74^2 = 76.8 m

Speed of second stone = 41.5 - 9.8 * 2.72 = 14.8 m/s

7 0
2 years ago
Type the correct answer in the box. Round your answer to the nearest whole number. Calculate the man’s mass. (Use PE = m × g × h
Blababa [14]

Answer:

56 kg

Explanation:

The change in potential energy of the man is given by:

\Delta U = mg \Delta h

where

m is the man's mass

g is the gravitational acceleration

\Delta h is the change in height of the man

In this problem, we have:

\Delta U=4620 J is the gain in potential energy

g = 9.8 m/s^2 is the gravitational acceleration

\Delta h=8.4 m is the change in height

Re-arranging the equation and substituting the numbers, we find the mass:

m=\frac{\Delta U}{g\Delta h}=\frac{4620 J}{(9.8 m/s^2)(8.4 m)}=56 kg

6 0
3 years ago
Read 2 more answers
A small charged sphere is attached to a thread and placed in an electric field. The other end of the thread is anchored so that
VMariaS [17]

Answer:

E = 9.66\times 10^{-6} N/C

direction is Horizontal

Explanation:

As we know that the string is horizontal here

so the tension force in the string is due to electrostatic force on it

now we will have

F = qE

so here the force is tension force on it

F = 6.57 \times 10^{-2} N

Q = 6.80 \times 10^3 C

now we have

6.57 \times 10^{-2} = (6.80 \times 10^3)E

E = 9.66\times 10^{-6} N/C

direction is Horizontal

4 0
3 years ago
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