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madam [21]
3 years ago
7

What Do You Already Know about Density? Material Design. Number each material and sort the items in order from lowest (1) to hig

hest (7) Density.
-Chalk
-Copper
-Flour
-Dry Beans
-Talcum Powder
-Wax
-Wet Sand
Physics
1 answer:
Elena-2011 [213]3 years ago
7 0

Answer:

1. Dry Beans - 591.75  kg/m^3

2. Flour - 593  kg/m^3

3. Wax - 900  kg/m^3

4. Wet sand - 2039 kg/m^3

5. Chalk - 2499 kg/m^3

6. Talcum Powder - 2776 kg/m^3

7. Copper - 8960  kg/m^3

Explanation:

Make sure your units are the same

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saad has mass 80kg when resting on the ground at the equator what will be the centripetal acceleration on saad if the radius of
Sidana [21]
Thank you for posting your question here at brainly. Below is the answer:

m = 80 kg
R = 6.4 x 10^6 m
Earth completes one rotation in 24 hours
Thus, T = 24 x 3600 s
Centripetral acceleration is given by 
ac = w^2R 
ac = (2 pie/T)^2R
ac = (2 pie/T)^2R = 4 pie^2/(24 x 3600)^2 x 6.4 x 10^6
ac = 0.034 m/s^2
8 0
3 years ago
What is a centripetal acceleration of a point on a bicycle wheel of a radius of 0.70 m when a bike is moving 8.0 m/s
Furkat [3]

Answer:

The acceleration of a point on the wheel is 11.43 m/s² acting radially inward.

Explanation:

The centripetal acceleration acts on a body when it is performing a circular motion.

Here, a point on the bicycle is performing circular motion as the rotation of the wheel produces a circular motion.

The centripetal acceleration of a point moving with a velocity v and at a distance of r from the axis of rotation is given as:

a=\frac{v^2}{r}

Here, v=8\ m/s,r=0.70\ m

∴ a=\frac{8}{0.70}=11.43\ m/s^2

Therefore, the acceleration of a point on the wheel is 11.43 m/s² acting radially inward.

3 0
3 years ago
A sound wave has frequency 620 Hz and wavelength 10.5 m. What is the speed of sound waves?
olasank [31]

Answer:

14

Explanation:

A sound wave in a steel rail has a frequency of 620 Hz and a wavelength of 10.5 m. What is the speed of sound in steel? U f = ? S f = 3 x 108 m/s) / 0.06 m 14 so it will be 14

7 0
2 years ago
A charge of 1.5 µC is placed on the plates of a parallel plate capacitor. The change in voltage across the plates is 36 V. How m
belka [17]

Answer:

Energy stored in the capacitor is U=2.7\times 10^{-5}\ J        

Explanation:

It is given that,

Charge, q=1.5\ \mu C=1.5\times 10^{-6}\ C

Potential difference, V = 36 V

We need to find the potential energy is stored in the capacitor. The stored potential energy is given by :

U=\dfrac{1}{2}q\times V

U=\dfrac{1}{2}\times 1.5\times 10^{-6}\times 36  

U = 0.000027 J

U=2.7\times 10^{-5}\ J

So, the potential energy is stored in the capacitor is U=2.7\times 10^{-5}\ J. Hence, this is the required solution.

4 0
3 years ago
Read 2 more answers
Sound waves cannot carry energy through. A water B air C a mirror D a vacuum
Ber [7]
I looked up the question and got D- a vacuum
3 0
3 years ago
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