Explanation:
<u>Forces</u><u> </u><u>on</u><u> </u><u>Block</u><u> </u><u>A</u><u>:</u>
Let the x-axis be (+) towards the right and y-axis be (+) in the upward direction. We can write the net forces on mass as
Substituting (2) into (1), we get
where , the frictional force on Set this aside for now and let's look at the forces on
<u>Forces</u><u> </u><u>on</u><u> </u><u>Block</u><u> </u><u>B</u><u>:</u>
Let the x-axis be (+) up along the inclined plane. We can write the forces on as
From (5), we can solve for <em>N</em> as
Set (6) aside for now. We will use this expression later. From (3), we can see that the tension<em> </em><em>T</em><em> </em> is given by
Substituting (7) into (4) we get
Collecting similar terms together, we get
or
Putting in the numbers, we find that . To find the tension <em>T</em>, put the value for the acceleration into (7) and we'll get . To find the force exerted by the inclined plane on block B, put the numbers into (6) and you'll get
Answer:
0.5 eV
Explanation:
= Initial potential energy =
= Final potential energy
= Initial width
= Final width =
Energy of an electron in a one-dimensional trap is given by
From the equation we get
So,
The ground state energy will be 0.5 eV
<span>gravitational force = 0.1 mg-wt. = 0.1 * 10^-6 * 9.8 N = Gm1m2/r^2
m1 = 40 kg m2 =15 kg and r = 0.2 m
Put in and find G</span>