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2 years ago

Explain why a battery causes charge to flow spontaneously when the battery is inserted in a circuit

1 answer:

3 0

Batteries supply electrons to the circuit by releasing negatively charged atoms or ions. These ions are produced by the batteries through a chemical reaction that spontaneously occurs within the battery. So the negative end of the battery pushes the ions towards the positive end of the circuit with the help of the voltage. This is why eventually, batteries "run out" when the electrode is used up and the chemical reaction can no longer continue.

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TRUE or FALSE: Most Electromagnetic waves are blocked by the atmosphere. True False

wariber [46]

True because the atmosphere is in the way

6 0

2 years ago

A box is placed on a 30o frictionless incline. What is the acceleration of the box as it slides down the incline

balandron [24]

Answer:

2.78m/s²

Explanation:

Complete question:

A box is placed on a 30° frictionless incline. What is the acceleration of the box as it slides down the incline when the co-efficient of friction is 0.25?

According to Newton's second law of motion:

$\sum F_x = ma_x\\F_m - F_f = ma_x\\mgsin\theta - \mu mg cos\theta = ma_x\\gsin\theta - \mu g cos\theta = a_x\\$

Where:

$\mu$ is the coefficient of friction

g is the acceleration due to gravity

Fm is the moving force acting on the body

Ff is the frictional force

m is the mass of the box

a is the acceleration'

Given

$\theta = 30^0\\\mu = 0.25\\g = 9.8m/s^2$

Required

acceleration of the box

Substitute the given parameters into the resulting expression above:

Recall that:

$gsin\theta - \mu g cos\theta = a_x\\$

9.8sin30 - 0.25(9.8)cos30 = ax

9.8(0.5) - 0.25(9.8)(0.866) = ax

4.9 - 2.1217 = ax

ax = 2.78m/s²

Hence the acceleration of the box as it slides down the incline is 2.78m/s²

5 0

2 years ago

A light bulb connects to a battery. A second, identical light bulb connects in parallel to the first light bulb. The connecting

mr Goodwill [35]

Answer:d

Explanation:

Suppose V is the voltage of battery and R is the resistance of bulb

so Power drop for initial stage

$P_1=\frac{V^2}{R}$

When another identical bulb of same resistance is applied in parallel so voltage Drop across both the resistor will be same i.e. V

so Power consumed $P_2=\frac{V^2}{R}$

so there is no change in power and hence no dip in brightness

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2 years ago

What does the thermosphere and stratmosphere have in common

Darya [45]

these include the troposphere (0 to 16 km), stratosphere (16 to 50 km), mesosphere (50 to 80km) and thermosphere (80 to 640km). The boundaries between these four layers are defined by abrupt changes in temperature, and include respectively the tropopause, stratopause and mesopause.

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3 years ago

Comment on the statement "Sharper the curve, more is the bending."

Tatiana [17]

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The passenger slides away from the centre of the curve.

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tan θ = v^2/rg

Sharper the curve, smaller is the radius and greater is the value of 0.

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1 year ago