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vladimir1956 [14]
3 years ago
7

A projectile is launched into the air with an initial speed of 40 m/s and a launch angle of 20° above the horizontal. The projec

tile lands on the ground five seconds later. Neglecting air resistance, calculate the projectile’s range and draw a projectile path.

Physics
1 answer:
miv72 [106K]3 years ago
7 0

Explanation:

V=40m/s

Vy=V.sina=40.sin20=40 . 0.342=13.68m/s

Vx=V.cosa=40.cos20=40 . 0.766=30.64m/s

Projectile travels during 5 seconds and the ramge becomes:

x=V.t=30.64 . 5=153.2m

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