Question

Liquid dimethyl disulfide (CH3SSCH3) flows through a pipe with a mass flow rate of 86.0 g's. Given that the density of dimethyl disulfide is 1.0625 g/cm, find: The molar flow rate in molimin: Number mol/min The volumetric flow rate in L/hr.

Answer 1

Explanation:

Molar mass of $CH_{3}SSCH_{3}$ is 94 g/mol. As it is known that number of moles is equal to mass of a substance divided by its molar mass.

Then, calculate the number of moles as follows.

     No. of moles = $\frac{86.0 g}{94 g/mol}$ in 1 s

                           = 0.914 mol

So, in 60 sec number of moles will be equal to 0.914 x 60 = 54.89 mol/min.

Hence, the molar flow rate = 54.89 mol/min

Also, density is equal to mass of a substance divided by its volume.

                    Density = $\frac{mass}{volume}$

                      Volume = $\frac{mass}{Density}$

                                     = $\frac{86.0 g}{1.0625 g/cm^{3}}$

                                     = 80.941 $cm^{3}$

As, 80.941 $cm^{3}$ of volume flows in 1 s . Therefore, flow of volume in 1 hour will be calculated as follows.

                 In 1 hr = 80.941 $cm^{3} \times 3600$

                            = 291388.24 $cm^{3}/hr$

Since, 1 $cm^{3}$ = 0.001 L.

So,              291388.24 $cm^{3}/hr \times 0.001 L/cm^{3}$

                            = 291.38824 L/hr

Thus, we can conclude that molar flow rate in mol/min is 54.89 mol/min and the volumetric flow rate in L/hr is 291.38824 L/hr.